Alphabet Test Questions and Answers

Answer: D

Correct answer: 24

Build the positions from the front. Ramu is 5th. Rani is six places after him, so Rani is 11th.

Rani is midway between Ramu and Raju, so Raju is as far beyond Rani as Rani is beyond Ramu - six more places, putting Raju 17th from the front.

Raju is also 8th from the last, so the class holds

\[ 17 + 8 - 1 = 24 \]

The subtraction avoids counting Raju twice, once from each end.

Answer: B

Correct answer: L

Seventeen letters counted from the end run from Z back to J, positions 10 to 26. Fourteen from the beginning run from A to N, positions 1 to 14.

The overlap is J to N, positions 10 to 14, and its middle is

\[ \frac{10+14}{2} = 12 \rightarrow L \]

As with the companion questions, the two counts overlap in the middle of the alphabet rather than meeting end to end, and it is the shared stretch whose midpoint is wanted.

Answer: E

Correct answer: Integument

Comparing letter by letter, the alphabetical order of the five words is:

Integument → Intellect → Intelligent → Intend → Intense

All five share Inte, so everything turns on the fifth letter: g, l, l, n, n. The g of Integument comes first, which is easy to miss because the word looks the least familiar of the five. Length and familiarity have no bearing on the order.

Answer: D

Specified letters from the left are N and O , and the letter from the right is I.
With these letters , according to the conditions given in the question , one Word ONION can be formed.
Clearly , first letter of this word is O.

Answer: C

When positions of first and the third alphabets of each of the words are interchanged, we have 
PAL TUB RAC NOS DIH
clearly, PAL and TUB are the only meaningful words. These words are obtained from LAP and BUT
respectively.

Answer: D

Correct answer: L

EXCELLENCE has ten letters, so the swaps pair 1 with 2, 3 with 4, 5 with 6, 7 with 8 and 9 with 10:

X E E C L L N E E C

Counting six from the right - C, E, E, N, L, L - the sixth is L, at the 5th position from the left.

With ten letters the count from the right can be converted directly: the 6th from the right is the 5th from the left.

Answer: C

Correct answer: V

Count from the right end first. Z is 1st, so the 11th from the right is at position

\[ 26 - 11 + 1 = 16 \rightarrow P \]

Six to the right of P is position 22:

\[ 16 + 6 = 22 \rightarrow V \]

The formula for counting from the right - 27 minus the count - avoids the off-by-one that catches most attempts at this kind of question.

Answer: C

Correct answer: R

Apply the three swaps to TRANSLATION: 1st with 7th (T and A), 2nd with 8th (R and T), 3rd with 9th (A and I). The word becomes

A T I N S L T R A O N

The 9th letter from the right, in eleven letters, is the 3rd from the left: I. Five to the right of it is the 8th letter, R.

The swaps must be made before any counting; counting first and swapping afterwards gives a different letter.

Answer: D

Correct answer: No such letter

H is the 8th letter and S the 19th, so the midpoint is

\[ \frac{8+19}{2} = 13.5 \]

which falls between M and N rather than on a letter. There are ten letters between H and S, an even number, so no single letter can sit exactly in the middle.

The check is quick: a midpoint letter exists only when the two positions have the same parity, and 8 and 19 do not.

Answer: C

Correct answer: S

Build the new arrangement first. The second half comes first, then the first half reversed:

N O P Q R S T U V W X Y Z M L K J I H G F E D C B A

Counting from the right, A is 1st and the 16th is X, at position 11 from the left. The 5th letter to the left of X is therefore at position 6, which is S - counting W, V, U, T, S without including X itself, which is the convention used throughout this set.