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Memory Management Questions and Answers

193.

Modems are configured in such a manner that any incoming calls are automatically answered. Manufacturer provides inbuilt modems in many user computers. In this case the greatest security risk when dealing with the modems is

Answer: B

Correct answer: Remote access without the knowledge of network administrator

A modem set to answer automatically gives anyone who dials it a way into the machine, and through it into the network, that bypasses the firewall and every other perimeter control. Because it is inside the network and unrecorded, the administrator has no way of knowing the door exists.

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Answer: A

Correct answer: the set of pages it has referenced in a recent interval

The working set is the set of pages a process has referenced within the most recent window of \( \Delta \) references. It is Denning’s model, and it is an approximation of the process’s current locality. Its purpose is practical. If every process is given enough frames to hold its working set, page faults stay rare and the system runs efficiently; if a process has fewer, it thrashes. The operating system therefore sums the working set sizes of all processes and, if the total exceeds the available frames, suspends one - freeing its frames for the rest rather than letting every process thrash together. The choice of window matters. Too small a \( \Delta \) misses part of the locality; too large a one spans several localities and overstates the requirement. Tracking it exactly is expensive, so it is approximated with reference bits sampled at intervals. The related control is page-fault frequency, which adjusts allocation by watching the fault rate directly rather than by measuring the working set.

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198.

Consider a computer with 8 Mbytes of main memory and a 128 K cache. The cache block size is 4 K. It uses a direct mapping scheme for cache management. How many different main memory blocks can map onto a given physical cache block ?

Answer: C

Correct answer: 64

There are \( 8\ \text{MB}/4\ \text{KB} = 2048 \) main memory blocks and \( 128\ \text{KB}/4\ \text{KB} = 32 \) cache lines. With direct mapping each line is shared by

\[ \frac{2048}{32} = 64 \]

different memory blocks, so any two of those 64 compete for the same line.

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