A convex lens has a 30 cm focal length in air. The focal length of the same convex lens in medium A is (given that the refractive index of air-medium A = 1.4, the refractive index for air-glass = 1.5):
DSSSB JE - 2023,
Answer: B
The focal length of a thin lens follows the lens maker's formula, \(1/f = (n_{rel} - 1)(1/R_1 - 1/R_2)\), where \(n_{rel}\) is the index of the lens relative to the surrounding medium. In air \(n_{rel} = 1.5\), so \(1/f_a = 0.5\,K\). In medium A, \(n_{rel} = 1.5/1.4\), so \(1/f_m = (1.5/1.4 - 1)K = 0.0714\,K\). Dividing:
\[ \begin{aligned} f_m = f_a \times \frac{0.5}{0.0714} \\ &= 0.30 \times 7 = 2.1\ \text{m} \end{aligned} \]The lens becomes much weaker because the glass and medium have nearly equal indices. The options 0.21 m and 0.11 m would need the focal length to shrink, which cannot happen when the surrounding index rises toward that of the lens.
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