Calendar Questions and Answers

Answer: B

Given that 2.12.91 is the first Tuesday
Hence we can assume that 4.12.91 is the first Thursday

If we add 7 days to 4.12.91, we will get second Thursday
If we add 14 days to 4.12.91, we will get third Thursday
If we add 21 days to 4.12.91, we will get fourth Thursday

=> fourth Thursday = (4.12.91 + 21 days) = 25.12.91.

Answer: A

First,we count the number of odd days for the left over days in the given period.

Here,given period is 15.8.2012 to 11.6.2013

Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun

16   30   31  30   31   31   28  31   30   31   11(left days)

2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days

So,given day Thursday + 6 = Wednesday is the required result.

Answer: B

Only the remainder on division by 7 matters - the odd days.

\[ 61 = 8 \times 7 + 5 \quad\Longrightarrow\quad 5 \text{ odd days} \]

Counting five days on from Monday:

\[ \text{Tue, Wed, Thu, Fri, } \mathbf{Sat} \]

The eight complete weeks return to Monday and contribute nothing.

Answer: C

Correct answer: Saturday

Only the remainder after dividing by 7 matters, since each complete week returns to the same day.

\[61 = 8 \times 7 + 5\]

Counting five days on from Monday gives Saturday.

Answer: B

1856 is a leap year, so its calendar returns after 28 years:

\[ 1856 + 28 = 1884 \]

Both must be leap years beginning on the same weekday, which the 28-year cycle ensures - and 1884 is indeed divisible by 4.

Answer: B

Each week is seven days, so

\[ x \text{ weeks } + x \text{ days} = 7x + x = 8x \text{ days} \]

The two \( x \)'s are added, not multiplied - \( 7x^{2} \) would be the result of multiplying them.

Answer: C

We know that,

Odd days --> days more than complete weeks

Number of odd days in 400/800/1200/1600/2000 years are 0.

Hence, the number of odd days in first 1600 years are 0.

Number of odd days in 300 years = 1

Number of odd days in 49 years = (12 x 2 + 37 x 1) = 61 days = 5 odd days

Total number of odd days in 1949 years = 1 + 5 = 6 odd days

Now look at the year 1950

Jan 26 = 26 days = 3 weeks + 5 days = 5 odd days

Total number of odd days = 6 + 5 = 11 => 4 odd days

Odd days :-

0 = sunday ;

1 = monday ;

2 = tuesday ;

3 = wednesday ;

4 = thursday ;

5 = friday ;

6 = saturday

Therefore, Jan 26th 1950 was Thursday.

Answer: B

A year is a leap year if it is divisible by 4, except that a century year must also be divisible by 400.

• 1900 ÷ 400 is not whole ✗
• 1700 ÷ 400 is not whole ✗
• 2500 ÷ 400 is not whole ✗
• \( 1200 \div 400 = 3 \) ✓

So 1200 has 366 days. All four are divisible by 4, which is exactly why the century rule is needed to separate them.

Answer: B

If the month in which you are born is completed in the present year i.e, your birthday, then

Your Age = Present year - Year you are born 

As of now, present year = 2018

i.e, Age = 2018 - 1995 = 23 years.

Answer: A

Correct answer: Thursday

2008 is a leap year, so it contains 366 days.

\[366 = 52 \times 7 + 2\]

That leaves 2 odd days, so the day advances by two: Tuesday becomes Thursday. An ordinary year would advance the day by only one.