An 8-bit register has bits 2:0 selecting a prescaler of two raised to that field. Writing 0x05 selects a prescaler of
Answer: C
Correct answer: 32
The field holds 5, and the prescaler is two raised to that field: \[ 2^5 = 32. \] Reading the register value as the divisor directly gives the 5 offered, and this is a common form for prescaler fields precisely because a three-bit field then spans divisors from 1 to 128.
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