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Polar and Nyquist Plots Questions and Answers

1.

The Nyquist diagram of a LTI system is shown in figure. The system is :

Nyquist plot: from omega = 0 below the real axis it crosses the negative real axis just left of the point minus 1, loops through the upper left quadrant and ends at the origin at omega = infinity

Exam Year(s)

RSMSSB JE - 2025, RSMSSB - 2025,

Answer: D

The system is stable.

By the Nyquist criterion, the closed-loop system is stable when the plot of the open-loop frequency response does not encircle the critical point −1 + j0 (for an open-loop system with no poles in the right half plane, which is the usual assumption in such questions).

The plot crosses the negative real axis between −1 and the origin, so the gain margin is greater than one and the point −1 lies outside the curve. A plot passing through −1 would mean marginal stability, and one enclosing it would mean instability. Strictly, a full test also needs the number of open-loop right-half-plane poles, which is why 'insufficient information' is tempting, but the question intends the standard reading.

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