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Algebra Questions and Answers

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111.

If a = -12 and b = -14 then 2a + 2b + 3 is

Answer: B

Substitute \( a = -12 \) and \( b = -14 \).

\[ 2a = -24, \qquad 2b = -28 \]

\[ -24 - 28 + 3 = -49 \]

Both doubled values stay negative; the \( +3 \) only softens the total slightly.

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112.

Which of the following is the numerical coefficient of x²y²?

Answer: A

The numerical coefficient is the number multiplying the variable part. Written in full, the term is

\[ x^{2}y^{2} = 1 \cdot x^{2}y^{2} \]

so the coefficient is 1. \( x^{2} \) and \( y^{2} \) are parts of the variable factor, not numbers.

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113.

If the expression \( 4c + 4b + 4d \) is subtracted from \( 3c + 4b + 5d \), then the answer will be

Answer: A

Subtracting flips every sign in the expression being taken away.

\[ (3c + 4b + 5d) - (4c + 4b + 4d) \]

\[ = (3c - 4c) + (4b - 4b) + (5d - 4d) \]

\[ = -c + d \]

The \( b \) terms cancel exactly, which is why no \( b \) survives.

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115.

The value of x² - 5 at x= -1 is -

Answer: C

Substitute \( x = -1 \), squaring before subtracting.

\[ x^{2} - 5 = (-1)^{2} - 5 = 1 - 5 = -4 \]

A negative number squared is positive, so \( (-1)^{2} = 1 \), not \( -1 \) - that slip would give \( -6 \).

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116.

In 15y and 160ab, coefficients are

Answer: D

The coefficient is the numerical factor of a term.

\[ 15y \rightarrow 15, \qquad 160ab \rightarrow 160 \]

The letters \( y \), \( a \) and \( b \) are the variable parts, not coefficients.

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117.

Algebraic expression of difference of 13x and 7y can be written as

Answer: B

"Difference of 13x and 7y" means the first minus the second.

\[ 13x - 7y \]

The two terms are unlike, so the subtraction cannot be carried out any further - \( 6xy \) would come from subtracting the coefficients and merging the variables, which is not a valid step.

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118.

Algebraic form of statement "sum of product of 2a and 2b and product of 12x and 2y" is

Answer: A

Form each product, then add them.

\[ 2a \times 2b = 4ab \]

\[ 12x \times 2y = 24xy \]

\[ \therefore\ 4ab + 24xy \]

Both coefficients multiply within their own product; the two products are then joined by addition, not multiplied together.

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120.

On solving expression 6a + 8b - 11a, answer will be

Answer: A

Only the \( a \) terms are alike.

\[ 6a - 11a = -5a \]

\[ \therefore\ -5a + 8b \]

Since \( 11 > 6 \), the result is negative; the \( 8b \) is unlike and stays put.

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