Puzzle Test Questions and Answers

Answer: C

Her second visit must be to F.

Z is first and H is third, so the second clinic is one of F, G, X or Y. G cannot be second, because F must come before G. X cannot be second, because G must come before X (and F before G). Y cannot be second, because F must come before Y.

Only F has no clinic that must precede it, so F must be second. A valid schedule is Z, F, H, G, X, Y, or Z, F, H, Y, G, X.

Answer: B

The French trainer visited on Wednesday. Number the days Sunday = 1 to Saturday = 7. Exactly four trainers come before Usama, so Usama (Chinese) is on day 5. Veer (Hindi) comes three days before the Chinese trainer, so Veer is on day 2. German and French trainers fall between Veer and Usama, on days 3 and 4. Qasim (English) is two days before the German trainer, which gives German on day 3 and Qasim on day 1, so French is on day 4. The Urdu trainer lies between Rahul and Usama and Tanuj is after Usama, so Urdu is on day 6, Rahul on day 7 and Tanuj on day 6. Sohan is not German, so Sohan is on day 4 and Pappu on day 3. Day 4 is Wednesday, the French trainer. German is Tuesday, Hindi Monday and Chinese Thursday.

Answer: D

E has the birthday on Wednesday. The days run Monday to Saturday. Only C has a birthday before F, so C is on Monday and F is on Tuesday. A is on Thursday. The remaining days, Wednesday, Friday and Saturday, belong to B, D and E. B comes immediately after D, so D and B take Friday and Saturday in that order, leaving Wednesday for E. F is on Tuesday, D on Friday and B on Saturday, so none of these can be Wednesday.

Answer: A

S is White. Only two boxes lie between the Brown box P and the Black box, so they are at the two ends. Brown is not at the top, so Black is on top and P is at the bottom. One box lies between Q and the Red box, so Q is the top Black box and the Red box is third.

White is then second. R is not White, so R is the Red box, and the remaining box S is White. Black, Brown and Red belong to Q, P and R.

Answer: C

E is the oldest. F is the youngest in position 6, and D differs from F by one year, so D is fifth. Two persons between A and E mean that they are at positions 1 and 4, since 2 and 5 or 3 and 6 are not possible with D at 5 and F at 6.

B is older than A, so A cannot be first. Then A is fourth and E is first. B and C fill the second and third places with B older than C. So E is the oldest, and A, B and C are not.

Answer: A

N joins the meeting on Friday. Number the days Monday 1 to Saturday 6. ‘Only M has to join the meeting before O’ means M is the only person who comes before O, so M is on Monday and O is on Tuesday. K is on Wednesday. That leaves Thursday, Friday and Saturday for N, P and L.

L joins after P with exactly one person between them, so P and L must be two days apart. Among Thursday, Friday and Saturday the only such pair is Thursday and Saturday, with P on Thursday and L on Saturday. N is left with Friday. P, L and O are therefore all on other days, which rules out options B, C and D.

Answer: B

S got 72 marks. R lives on an even floor that is not 2, so R is on floor 4. Two children live between R and the one with 93 marks, so the 93-mark child is on floor 1. One child lives between the 93-mark and 56-mark children, so 56 marks belong to the child on floor 3. Q got the highest marks, 93, so Q is on floor 1, and S lives immediately above Q on floor 2. T got 35 marks.

The remaining children P and T take floors 3 and 5. The 56-mark child is on floor 3 and T has 35, so T is on floor 5 and P is on floor 3 with 56. R on floor 4 did not get 72, so R has 81, and the last mark, 72, goes to S. P, T and Q hold 56, 35 and 93, so options A, C and D are wrong.

Answer: B

Two boxes lie between F and D. Number the positions 1 to 6 from the top. D is second last, so D is 5. Three boxes are between D and C, so C is 1. Four boxes are between C and G, so G is 6. One box is between D and E, so E is 3. The remaining positions 2 and 4 go to F and H, and F is above H, so F is 2 and H is 4.

Between F (2) and D (5) are positions 3 and 4, so two boxes. One and three miscount that gap, and zero would need F and D to be adjacent.

Answer: A

Yashika was born in 2000. Nitu and Monika are 14 years apart and Monika was born before 1993, so Monika is 1990 and Nitu is 2004. Saanvi is 3 years younger than Monika, so Saanvi is 1993. The years left are 1997, 2000 and 2002. Divya is 5 years older than Tania, which fits only 1997 and 2002, so Divya is 1997 and Tania is 2002. That leaves 2000 for Yashika.

1993 is Saanvi's year, 2002 is Tania's and 1997 is Divya's.

A check on the years: Nitu (2004) is 14 years younger than Monika (1990), Saanvi (1993) is 3 years younger than Monika, and Divya (1997) is 5 years older than Tania (2002).

Answer: D

Only four persons live between Cheema and Deepanshu. Bindu is just below Cheema and both are above floor 4, so Bindu is on 5 and Cheema on 6. Cheema is three floors above Aarush, so Aarush is on 3. Gopal is two floors below Harish; of the free floors 1, 2 and 4 the only pair two apart is Gopal on 2 and Harish on 4, which leaves Deepanshu on 1, not adjacent to Aarush as required. Floors 2, 3, 4 and 5 lie between 1 and 6, so four persons live between Cheema and Deepanshu. Harish is two floors, not one, above Gopal. Aarush (3) is not just above Bindu (5), and only one person (on floor 4) lives between Aarush and Bindu.