If computer A execute a program in 10 seconds and computer B runs same in 15 seconds, how much faster is computer A than computer B
Answer: B
Correct answer: 1.5 times
Performance is the reciprocal of execution time, so the ratio of performances is the inverse ratio of times:
\[ \frac{\text{Performance}_A}{\text{Performance}_B}=\frac{\text{Time}_B}{\text{Time}_A}=\frac{15}{10}=1.5 \]
Computer A is therefore 1.5 times as fast as computer B.
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