The expression (11.98*11.98+11.98*x+0.02*0.02) will be a perfect square for x equal to:
Answer: A
The expression is set up to be the square of a sum. Comparing with
\[ (a+b)^{2} = a^{2} + 2ab + b^{2} \]
the outer terms give \( a = 11.98 \) and \( b = 0.02 \), so the middle term must be
\[ 2ab = 2(11.98)(0.02) = 0.4792 \]
The middle term as written is \( 11.98x \), so
\[ 11.98x = 0.4792 \quad\Longrightarrow\quad x = 2(0.02) = 0.04 \]
The square is then \( (11.98 + 0.02)^{2} = 12^{2} = 144 \). Notice the shortcut: \( x \) is simply twice the smaller number, so the decimals never need multiplying out.
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