Machine-translated by Google. Questions are authored in English.
Top

Interpretation of Data Questions and Answers

Direction for [ Question No: 21 To 22 ] :

Directions : The following questions are based on the following diagram :

The following is a diagram of a certain college showing the number of students passed and failed during the years 2012 to 2015 :

YearNumber of Students (total)Passed
2012500200
2013700400
2014800500
20151000700

(The diagram is a stacked bar chart: each bar shows the total, with the passed students as the lower, hatched part and the failed students above it.)

21.

In which year is the percentage of passing of students maximum ?

Exam Year(s)

MH SET - 2021, SET Exam - 2021,

Answer: D

The pass percentage is highest in 2015.

\[ \begin{aligned} 2012: \frac{200}{500} &= 40\% \\ 2013: \frac{400}{700} &\approx 57.1\% \\ 2014: \frac{500}{800} &= 62.5\% \\ 2015: \frac{700}{1000} &= 70\% \end{aligned} \]

The pass rate rises every year, reaching 70% in 2015. 2014 has more passes than 2013 but a lower rate than 2015, and 2012 is the lowest at 40%. Read the hatched part of each bar as the passes, not the whole bar.

Please log in or register to report this question.

22.

The percentage of passing of students in examination for all the years 2012 to 2015 combined together is ..................... .

Exam Year(s)

MH SET - 2021, SET Exam - 2021,

Answer: C

The combined pass percentage is 60.

Add the passes and the totals over all four years before dividing:

\[ \begin{aligned} \text{passed} &= 200 + 400 + 500 + 700 = 1800 \\ \text{total} &= 500 + 700 + 800 + 1000 = 3000 \\ \frac{1800}{3000} &= 60\% \end{aligned} \]

Averaging the four yearly rates instead gives about 57.4%, close to the 57.14 option, which is only 2013's rate. 70 is 2015's rate alone, and 50 has no basis in the data.

Please log in or register to report this question.

Direction for [ Question No: 23 To 24 ] :

The following questions are based on the following information :

Among 800 students 220 failed in Marathi, 300 failed in English, 150 failed in Hindi, 125 failed in both Marathi and English, 70 failed in both Marathi and Hindi, 60 failed in both English and Hindi. 30 failed in all the three languages.

23.

How many students failed in exactly two languages ?

Exam Year(s)

MH SET - 2020, SET Exam - 2020,

Answer: B

165 students failed in exactly two languages.

Each 'failed in both' figure includes the 30 who failed in all three, so subtract 30 from each pair:

\[ \begin{aligned} \text{M and E only} &= 125 - 30 = 95 \\ \text{M and H only} &= 70 - 30 = 40 \\ \text{E and H only} &= 60 - 30 = 30 \\ \text{total} &= 95 + 40 + 30 = 165 \end{aligned} \]

255 is the raw sum 125 + 70 + 60, which counts the all-three group three times, and 195 subtracts the 30 only twice instead of three times. 250 is the number who failed in only one language (Q34).

Please log in or register to report this question.

24.

How many failed in only one language ?

Exam Year(s)

MH SET - 2020, SET Exam - 2020,

Answer: C

250 students failed in only one language.

For each language subtract the two pairs that include it and add back the 30 who were subtracted twice:

\[ \begin{aligned} \text{Marathi only} &= 220 - 125 - 70 + 30 = 55 \\ \text{English only} &= 300 - 125 - 60 + 30 = 145 \\ \text{Hindi only} &= 150 - 70 - 60 + 30 = 50 \\ \text{total} &= 55 + 145 + 50 = 250 \end{aligned} \]

Check: 250 in one language, 165 in exactly two and 30 in all three make 445 who failed at least once, which agrees with \(670 - 255 + 30 = 445\). 165 is the exactly-two count, and 195 and 255 are wrong pair totals.

Please log in or register to report this question.

Direction for [ Question No: 25 To 26 ] :

The following questions are based on the following diagram :

The following is a diagram of a company ABC showing the quantity of a certain goods exported in lakh units and the revenue generated in crores of rupees for the years 2011 to 2015 :

YearQuantity exported (lakh units)Revenue generated (crore rupees)
20111020
2012515
20131535
20142040
20153050

25.

In which year the revenue generated per unit exported is maximum ?

Exam Year(s)

MH SET - 2020, SET Exam - 2020,

Answer: A

Revenue per unit exported is highest in 2012.

Divide the revenue by the quantity for each year. Revenue is in crores and quantity in lakhs, and one crore is 100 lakh, so crores per lakh units times 100 gives rupees per unit:

\[ \begin{aligned} 2011 &: 20/10 \times 100 = 200 \\ 2012 &: 15/5 \times 100 = 300 \\ 2013 &: 35/15 \times 100 \approx 233 \\ 2014 &: 40/20 \times 100 = 200 \\ 2015 &: 50/30 \times 100 \approx 167 \end{aligned} \]

2012 has the smallest export of the five years but the highest return per unit, Rs. 300. 2015 has the largest revenue and quantity, but the lowest revenue per unit, and 2013 and 2014 fall in between.

Please log in or register to report this question.

26.

What is the average (arithmetic mean) per unit revenue generated during 2011 to 2015 :

Exam Year(s)

MH SET - 2020, SET Exam - 2020,

Answer: B

The key's answer is Rs. 200, the average revenue per unit over the whole period.

Taking the five years together, divide total revenue by total quantity exported:

\[ \begin{aligned} \text{revenue} &= 20+15+35+40+50 = 160\ \text{crore} \\ \text{quantity} &= 10+5+15+20+30 = 80\ \text{lakh} \\ \text{per unit} &= \tfrac{160}{80} \times 100 = \text{Rs. } 200 \end{aligned} \]

Averaging the five yearly figures instead (200, 300, 233, 200 and 167) would give about Rs. 220, which is not among the options, so the key uses the overall ratio. Rs. 166, Rs. 233 and Rs. 300 are the single-year figures for 2015, 2013 and 2012.

Please log in or register to report this question.

Direction for [ Question No: 27 To 28 ] :

Direction : The following questions are based on the following pie-diagram :

(The pie-diagram is given here as a table of its labelled shares.)

SectorShare
A : Printing cost35%
B : Cost of paper20%
C : Royalty15%
D : Advertisement charges20%
E : Other chargesx%

27.

If the cost of paper is Rs. 16,000, then find the amount of other charges :

Exam Year(s)

MH SET - 2019, SET Exam - 2019,

Answer: C

The other charges amount to Rs. 8,000.

The shares must total 100%, so other charges are \(x = 100 - (35 + 20 + 15 + 20) = 10\%\). Paper is 20% and costs Rs. 16,000:

\[ \begin{aligned} \text{total} &= 16000 \div 0.20 = 80000 \\ \text{other} &= 10\% \times 80000 = 8000 \end{aligned} \]

Rs. 16,000 assumes other charges equal paper, and Rs. 12,000 is the royalty (15%), not the other charges.

Please log in or register to report this question.

28.

The tax deducted at source is 10% of the royalty amount then the amount of tax paid is ............... .

Exam Year(s)

MH SET - 2019, SET Exam - 2019,

Answer: A

The tax paid is Rs. 1,200.

From the same pie-diagram, the total cost is Rs. 80,000 (paper, 20%, is Rs. 16,000), and royalty is 15% of it.

\[ \begin{aligned} \text{royalty} &= 15\% \times 80000 = 12000 \\ \text{TDS} &= 10\% \times 12000 = 1200 \end{aligned} \]

Rs. 800 is 10% of the other charges, Rs. 1,000 is a rounded guess, and Rs. 8,000 is the other charges themselves.

Please log in or register to report this question.

Direction for [ Question No: 29 To 30 ] :

Direction : The following questions are based on the following information :

StateTotal number of male & female employeesRatio of number of males to that of female employeesPercentage of post-graduate among total employees
A20,00013 : 760
B30,0008 : 750
C25,0005 : 564
D40,00014 : 672
E10,0006 : 442

29.

Find the number of male employees in state D :

Exam Year(s)

MH SET - 2019, SET Exam - 2019,

Answer: C

State D has 28,000 male employees.

State D has 40,000 employees in the ratio of males to females 14 : 6, so males are 14 parts out of 20:

\[ \frac{14}{20} \times 40000 = 28000 \]

14,000 and 6,000 just read the ratio terms as thousands, and 20,000 is half the total.

Please log in or register to report this question.

30.

Find the number of post-graduate female employees in state B :

Exam Year(s)

MH SET - 2019, SET Exam - 2019,

Answer: D

State B has 7,000 post-graduate female employees.

State B has 30,000 employees in the ratio 8 : 7, so females are 7 parts out of 15, and 50 percent of employees are post-graduates. Applying that percentage to the female employees:

\[ \begin{aligned} \text{females} &= \tfrac{7}{15} \times 30000 = 14000 \\ \text{PG females} &= 50\% \times 14000 = 7000 \end{aligned} \]

15,000 is the number of all post-graduates in state B, 8,000 is half the male employees (16,000), and 350 is a decimal slip.

Please log in or register to report this question.

Loading…

Other Subjects

Tags: Interpretation of Data Questions and Answers