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Methods of Estimating Quantities Questions and Answers

1.

A room with inner-to-inner dimensions 4.8 m × 4.8 m is built by 20 cm thick walls all around. Calculate the central line length of walls.

Exam Year(s)

DSSSB JE - 2023,

Answer: B

The centre line of a wall lies half a wall thickness outside the inner face. For a room of 4.8 m x 4.8 m inner dimensions with 20 cm thick walls, each side of the centre-line rectangle is 4.8 + 0.2 = 5.0 m, so

\[ L = 4 \times 5.0 = 20\ \text{m} \]

The value 22.6 m would result from adding the thickness twice to each side (the outer dimension, 5.2 m, around), and 15.9 m and 14 m are not consistent with these dimensions.

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2.

Find the dry volume of the concrete required for 200 m\(^2\) of 20 cm thick concrete work with proportion of 1 : 2 : 4.

Exam Year(s)

DSSSB JE - 2023,

Answer: B

The volume of concrete work is area times thickness: \(200 \times 0.20 = 40\ \text{m}^3\). That is the wet volume. To get the dry volume of the ingredients, the wet volume is multiplied by 1.54, to allow for the voids and for the shrinkage of the dry materials when they are wetted and compacted:

\[ 40 \times 1.54 = 61.6\ \text{m}^3 \]

The value of 54.3 m\(^3\) is 1.36 times and 76.4 and 80 m\(^3\) are larger factors (1.91 and 2.0), which do not correspond to the usual bulking and shrinkage factor of 1.54 to 1.57.

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3.

Which the following statements applicable to lead and lift as per IS:1200-part-1-1992 are correct?

1. Lead: Distances not exceeding 250 m should be measured in units of 50 m.

2. Lift: Lift should be measured in units of 1.5 m from the ground level.

Exam Year(s)

DSSSB JE - 2023,

Answer: C

Both statements are correct, as the key shows. IS 1200 (Part 1) on the method of measurement of earthwork gives the rule that the lead, the distance that the excavated material is carried, is measured in units of 50 m for distances up to 250 m, and that the lift (the vertical height raised) is measured in units of 1.5 m from the ground level. The options that call either statement incorrect are rejected by the key. I could not check the clause text itself.

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4.

A tank is excavated in a level ground to a depth of 8 m with uniform side slopes. The top of the tank at ground level is rectangular in shape of size 40 × 20 m, while the bottom is of size 24 × 12 m. Compute the volume of earthwork by the trapezoidal rule.

Exam Year(s)

DSSSB JE - 2023,

Answer: D

The volume of earthwork by the trapezoidal rule is the mean of the end areas times the depth. The top area is \(40 \times 20 = 800\) m\(^2\) and the bottom area is \(24 \times 12 = 288\) m\(^2\):

\[ \begin{aligned} V = \frac{800 + 288}{2} \times 8 = 544 \times 8 \\ &= 4352\ \text{m}^3 \end{aligned} \]

The prismoidal formula would give a slightly smaller value (about 4181 m\(^3\)), and the other options are different from both rules.

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5.

Number of nominal bricks required for 15 m3 of brick work is approximately: (consider nominal size of bricks)

Exam Year(s)

RSMSSB JE - 2025, RSMSSB - 2025,

Answer: A

About 7500 bricks are needed.

The nominal size of a modular brick, including the mortar joint, is 20 cm × 10 cm × 10 cm, so one brick occupies 0.002 m3 of brickwork:

\[ \begin{aligned} \text{bricks per m}^3 &= \frac{1}{0.002} = 500 \\ 15 \times 500 &= 7500 \end{aligned} \]

6750, 7200 and 6000 correspond to 450, 480 and 400 bricks per cubic metre, none of which is the nominal-size figure.

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