Calendar Questions and Answers

Answer: C

We know that,

Odd days --> days more than complete weeks

Number of odd days in 400/800/1200/1600/2000 years are 0.

Hence, the number of odd days in first 1600 years are 0.

Number of odd days in 300 years = 1

Number of odd days in 49 years = (12 x 2 + 37 x 1) = 61 days = 5 odd days

Total number of odd days in 1949 years = 1 + 5 = 6 odd days

Now look at the year 1950

Jan 26 = 26 days = 3 weeks + 5 days = 5 odd days

Total number of odd days = 6 + 5 = 11 => 4 odd days

Odd days :-

0 = sunday ;

1 = monday ;

2 = tuesday ;

3 = wednesday ;

4 = thursday ;

5 = friday ;

6 = saturday

Therefore, Jan 26th 1950 was Thursday.

Answer: B

A year is a leap year if it is divisible by 4, except that a century year must also be divisible by 400.

• 1900 ÷ 400 is not whole ✗
• 1700 ÷ 400 is not whole ✗
• 2500 ÷ 400 is not whole ✗
• \( 1200 \div 400 = 3 \) ✓

So 1200 has 366 days. All four are divisible by 4, which is exactly why the century rule is needed to separate them.

Answer: B

If the month in which you are born is completed in the present year i.e, your birthday, then

Your Age = Present year - Year you are born 

As of now, present year = 2018

i.e, Age = 2018 - 1995 = 23 years.

Answer: A

Correct answer: Thursday

2008 is a leap year, so it contains 366 days.

\[366 = 52 \times 7 + 2\]

That leaves 2 odd days, so the day advances by two: Tuesday becomes Thursday. An ordinary year would advance the day by only one.

Answer: A

Weekend means Saturday & Sunday together. In total we have 52 weeks in a year. So there are 52 weekends in a year.

In normal we have 104 Weekend Days.

 We know that a Each normal year has 365 days or 52 weeks plus one day, and each week has two weekend days, which means there are approximately 104 weekend days each year.
Whereas in a leap year we have 366 days it adds one more day to the year. And what makes the change is the starting day of the year.

Answer: B

1 December 1991 is a Sunday, so the first Tuesday is the 3rd.

\[ \text{Tuesdays: } 3, 10, 17, 24, 31 \]

The fourth is 24.12.91. The 17th is the third Tuesday, which is why it appears as a distractor.

Answer: B

2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
Hence, the day on 2nd Jan 1901 was Wednesday.

Answer: C

Let today be \( D \). Yesterday is \( D - 1 \).

Suppose that day were tomorrow instead. If \( D - 1 \) is tomorrow, then "today" in that shifted week is \( D - 2 \), and we are told it would be Friday:

\[ D - 2 = \text{Friday} \quad\Longrightarrow\quad D = \textbf{Sunday} \]

Checking: if today were Sunday, yesterday was Saturday; treating Saturday as tomorrow puts today at Friday, as required.

Answer: B

Only the remainder on division by 7 matters - the odd days.

\[ 61 = 8 \times 7 + 5 \quad\Longrightarrow\quad 5 \text{ odd days} \]

Counting five days on from Monday:

\[ \text{Tue, Wed, Thu, Fri, } \mathbf{Sat} \]

The eight complete weeks return to Monday and contribute nothing.

Answer: D

Count the odd days backwards from 2013 until they total a multiple of seven.

\[ 2012:2,\ 2011:1,\ 2010:1,\ 2009:1,\ 2008:2,\ 2007:1,\ 2006:1,\ 2005:1,\ 2004:2,\ 2003:1,\ 2002:1 \]

\[ \text{total} = 14 \quad\Longrightarrow\quad 0 \text{ odd days} \]

So 2013 repeats the calendar of 2002.