A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is
Answer: C
Let the son's present age be \(x\) years .
Then, man's present age = \((x + 24) \) years
\(\Rightarrow (x + 24) + 2 = 2(x + 2)\)
\(\Rightarrow x + 26 = 2x + 4\)
So, \(x = 22\)
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Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times . Then age of Sivagami is :
Answer: D
Let Meena’s age = \(A\)
Then Sivagami’s age = \(A+2\)
After 6 years the total of their ages will be 7 times of what?
Not clear.
So the given data are inadequate.
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Five years ago, John’s age was half of the age he will be in 8 years. How old is he now?
Answer: B
Let John's present age be \(x\)
\(\therefore \) \(x-5=\) \(\frac{1}{2}\left ( x+8 \right )\)
\(\Rightarrow \) \(x-5=\) \(\frac{1}{2}x +4\)
\(\Rightarrow \) \(\frac{1}{2}x=9\)
\(\Rightarrow \) \(x=18\)
Hence, John's is 18 years old.
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Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age?
Answer: D
Given that:
1. The difference of age b/w R and Q = The difference of age b/w Q and T.
2. Sum of age of R and T is 50 i.e. (R + T) = 50.
Question : R - Q = ? .
Explanation:
R - Q = Q - T
(R + T) = 2Q
Now given that, (R + T) = 50
So, 50 = 2Q and therefore Q = 25.
Question is (R - Q) = ?
Here we know the value(age) of Q (25), but we don't know the age of R.
Therefore, (R-Q) cannot be determined.
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If 6 years are subtracted from the present age of Arun and the remainder is divided by 18, then the present age of his grandson Gokul is obtained. If Gokul is 2 years younger to Madan whose age is 5 years, then what is the age of Arun ?
Answer: C
Let the Present age of arun is \(x \)
Gokul's age = 5-2 = 3
\(\therefore\) \(\frac{x-6}{18}=3\)
\(\Rightarrow x-6=54\)
\(x=60\)
Arun's present age = 60 years
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Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4, what will be the total of their present age?
Answer: C
Let present age of P and Q be \(3x\) and \(4x\) respectively.
\(\left ( 3x-10 \right )=\frac{1}{2}\left ( 4x-10 \right )\)
\(\Rightarrow\) \(6x-20=4x-10\)
\(\Rightarrow\) \(2x=10\)
\(\Rightarrow \) \(x=5\)
Total of their present age is
\(=3x+4x=7x=7×5=35\)
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The ratio of Karthik’s and Kalyan’s ages is 4: 5. If the difference between the present age of Kalyan and the age of Karthik 5 years hence is 3 years, then what is the total of present ages of Karthik and Kalyan?
Answer: D
Let us consider Karthik as K1 and Kalyan as K2.
Given \(\frac{k1}{8+k1}\) and \(K2 - (K1 + 5) = 3 \)
\(K2 - K1 = 8\)
\(K2 = 8 + K1\)
Now,
\(\frac{k1}{8+k1}\) = \(\frac{4}{5}\)
k1 = 32 years
\(\therefore k2=40\) years
k1 + k2 = 72 years
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When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ?
Answer: B
Let the Father be \(x\) years when he died.
Average Age 10 years ago be \(A\)
Total Age 10 years ago = \(6A\)
Total Age after 10 years(Just before father's Death) = \( 6A + 6*10 = 6A + 60\)
Father Died and Baby was born => the Total number of people in the family is Same (6)
Baby born today so age of baby = 0
\((6A +60 - x)/6 = 6A/6\)
\(\Rightarrow A + 10 -(x/6) = A \)
\(\Rightarrow x/6 = 10 \)
\(\Rightarrow x = 60\)
Therefore we can conclude that the father was 60 years old when he died.
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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Answer: B
Let their present ages be \(4x, 7x \) and \(9x\) years respectively
Then, \((4x - 8) + (7x - 8) + (9x - 8) = 56\)
\(\Rightarrow 20x = 80\)
\(\Rightarrow x=4\)
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A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ?
Answer: C
By trial and error method from the given options,
as \(54-45=\left ( \frac{1}{11} \right )*\left ( 45+54 \right )=\frac{99}{11}=9\)
Hence this satisfies the given conditions.
Then the woman's husband age is 54.
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