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Nanochemistry Questions and Answers

41.

Halving a quantum dot's diameter, with confinement energy varying as the inverse square of the size, multiplies that energy by

Answer: A

Correct answer: 4

With \( E \propto 1/d^2 \), halving the diameter multiplies the confinement energy by \[ \left(\frac{1}{1/2}\right)^2 = 4. \] This is why quantum dot emission is so sensitive to size: a modest change in diameter moves the band gap enough to shift the colour visibly, which is the basis of tunable dot phosphors.

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42.

Match the material with its dimensionality.

1. Quantum dot   2. Carbon nanotube   3. Graphene

P. One dimensional   Q. Zero dimensional   R. Two dimensional

Answer: B

Correct answer: 1-Q, 2-P, 3-R

The dimensionality counts the directions in which carriers are free to move. A quantum dot confines them in all three, so it is zero-dimensional and has discrete atom-like levels. A nanotube leaves one direction free and is one-dimensional. Graphene leaves two free and is two-dimensional.

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43.

Match the technique with what it measures.

1. Scherrer analysis of X-ray broadening   2. Dynamic light scattering   3. Transmission electron microscopy

P. Hydrodynamic diameter in suspension   Q. Crystallite size   R. Size and shape seen directly

Answer: C

The three give different sizes for the same sample, because each measures a different thing: the crystallite, the diffusing body with its coating, and the visible outline. Quoting a size without naming the method is meaningless.

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44.

Put these steps of a chemical reduction synthesis in order.

1. Add the reducing agent   2. Purify and characterise the particles   3. Nuclei form and grow into particles   4. Dissolve the metal salt with a capping agent

Answer: D

The salt and the stabiliser go in first, reduction generates the atoms, nuclei form and grow under the capping agent's control, and the product is then cleaned up. Adding the reductant to an unstabilised solution gives agglomerates.

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45.

Consider the following statements about nanomaterials.

1. Surface to volume ratio rises as particle size falls   2. A metal nanoparticle melts above the bulk melting point   3. A smaller quantum dot emits at a shorter wavelength

Answer: A

Correct answer: 1 and 3 only are correct

Statements 1 and 3 are correct: the ratio goes as \( 1/d \), and a smaller dot has a wider gap and so emits at a shorter wavelength. Statement 2 has the sign wrong - the melting point is depressed, not raised, because surface atoms are less tightly bound. Gold nanoparticles a few nanometres across melt hundreds of degrees below bulk gold.

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Answer: B

Correct answer: high-energy ball milling

Milling breaks a coarse powder down and is therefore top-down. Chemical reduction of a salt, the sol-gel process and chemical vapour deposition all build the material up from atoms or molecules, which is what bottom-up means - and which is why all three give better control of size than milling does.

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Answer: C

Correct answer: their depressed melting point

A lower melting point is a genuine nanoscale effect but it works against catalytic use rather than for it: it is exactly why nanoparticle catalysts sinter and lose activity at high temperature. The three real reasons are the large area per unit mass, the unsatisfied surface bonds, and the high proportion of edge and corner atoms.

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48.

A nanoparticle catalyst loses activity after prolonged use at high temperature although no poison is present. The likely cause is

Answer: D

Correct answer: sintering of the particles into larger ones

Nanoparticles are thermodynamically driven to coalesce, and heat supplies the mobility to do it. Larger particles have a smaller surface to volume ratio and fewer edge and corner sites, so the activity falls even though the metal is chemically unchanged. Supports and spacers exist largely to keep particles apart and delay this.

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49.

A gold colloid prepared without a capping agent turns from red to grey within minutes. The explanation is

Answer: A

Correct answer: the particles have aggregated and settled

A gold colloid is red because of the plasmon resonance of well-separated particles. With no capping agent the surface energy drives them together, the resonance shifts and broadens as they couple, and the aggregates eventually grow large enough to scatter and settle - giving grey. Dissolution would leave a clear solution rather than a grey one.

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Answer: B

The smaller the particle the larger the proportion of those weakly bound surface atoms, so less energy is needed to disrupt the whole lattice. The depression can amount to hundreds of degrees for a particle a few nanometres across.

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