The flow of oil of density 800 kgm-3 through a horizontal pipe is streamlined. If the pressure between two points separated by 1m in the tube falls by 1.6 Nm-2, then the change in kinetic energy per kg of the liquid between these points is
KEAM - 2026,
Answer: B
The change in kinetic energy per kg is \(2 \times 10^{-3}\) J kg-1.
For a horizontal pipe, Bernoulli's equation gives \(\Delta p = \Delta\left(\tfrac{1}{2}\rho v^{2}\right)\). Dividing by the density gives the change in kinetic energy per unit mass.
\[ \begin{aligned} \frac{\Delta p}{\rho} &= \frac{1.6}{800} \\ &= 2 \times 10^{-3}\ \text{J kg}^{-1} \end{aligned} \]
The 1 m separation does not enter the calculation. \(16 \times 10^{-4}\) and \(8 \times 10^{-4}\) come from misplacing the decimal or halving.
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