Direction Sense Test Questions and Answers

Answer: C

Place Ram's house at the origin. Ram goes 3 km north, 2 km west, 3 km south and 5 km east, ending 3 km east of his house. Rohan goes 5 km south, 1 km east, 5 km north and 5 km west, so he ends 4 km west of his own start.

\[ x_R - 4 = 3 \Rightarrow x_R = 7 \]

Rohan's house is on the same line as Ram's, at 7 km to the east. So the shortest distance between the houses is 7 km. The options 9, 6 and 5 km do not agree with this meeting point.

Answer: B

Gagan is walking south. Take north as up. He starts walking south for 10 m. Turning left from south he faces east and walks 20 m. A 135 degree turn to the right (clockwise) from east takes him through south to south-west, and he walks 30 m south-west. Turning left from south-west he faces south-east and walks 40 m. A final 45 degree turn to the right (clockwise) from south-east turns him to face south.

North, east and west would need a different turn at one of these steps, for example a left turn at the last step would give east.

Answer: D

Karan ends 3 km north of his starting point. Take the start as (0, 0). West 7 km gives (-7, 0). A right turn from west faces north, so 3 km gives (-7, 3). Another right turn faces east, so 11 km gives (4, 3). A left turn faces north, so 4 km gives (4, 7). Two more left turns face west and then south: 4 km west gives (0, 7) and 4 km south gives (0, 3).

The final point is directly above the start, so the answer is North and 3 km. East and 4 km, South and 3 km and West and 4 km come from mixing up a left and a right turn.

Answer: C

Seema must cover 13 km. Take City L as the origin. J is 5 km east of L, K is 14 km west of J so K is 9 km west of L, and Seema is 3 km west of K, which is 12 km west of L. City M is 5 km north of L. So Seema is 12 km west and M is 5 km north of the same line. The shortest distance is the straight line: the square root of 12 squared plus 5 squared, which is the square root of 169, that is 13 km. The other facts about N, G and H are not needed. 11, 12 and 14 km are not the hypotenuse of a 12 and 5 right triangle.

Answer: B

Suppose Manish started facing some direction d. After the first right turn he faces 90 degrees clockwise from d, after the second right turn he faces 180 degrees from d, and the turn to the left brings him back to 90 degrees clockwise from d. At the end he is moving towards the south, so the direction 90 degrees clockwise from d is south. South is 90 degrees clockwise from east, so d is east. Manish started his journey going east, option (B). Starting north, south or west would leave him facing a different direction in the end.

Answer: A

He is 20 m east of the starting point. In the morning the Sun is in the east, so the first walk is 10 m east. A right turn from east faces south, so he walks 10 m south. A right turn from south faces west, so he walks 10 m west. A left turn from west faces south, so he walks 10 m south. Then 20 m east, and 20 m north. East-west total: \(+10 - 10 + 20 = 20\) east. North-south total: \(-10 - 10 + 20 = 0\). So he is 20 m due east of A. The 20 m west and the 10 m options come from taking a wrong turn direction at one of the turns.

Answer: D

Kunal moves from A 10 Km northwards upto B, then moves 6 Km southwards upto C, turns towards east and moves 3 km upto D.
Then AC = (AB-BC) = 4 Km

So Kunal distance from starting point A
\begin{aligned}
AD = \sqrt{AC^2 + CD^2} \\
= \sqrt{4^2+3^2} \\
= \sqrt{25} = 5
\end{aligned}

So AD is 5 Km also with reference to starting point Kunal's direction is North-East.

Answer: A

In the morning sun rises in the East. Hence then any shadow falls in the West. Since Nikharia's shadow was exactly to the right of Nivedita. Hence Nikharia is facing towards North.

Answer: B

Correct answer: 13 km

The northward legs come to \( 2 + 3 = 5 \) km and the eastward to \( 10 + 2 = 12 \) km. By Pythagoras the distance is \[ \sqrt{5^2 + 12^2} = \sqrt{169} = \mathbf{13}\text{ km} \]

Answer: A

Correct answer: 32 m, South

Adding the legs: west 15, then south 20, then east 15, then south 12. The east and west cancel, leaving \( 20 + 12 = 32 \) metres. So Jayant is 32 m south of X.