Which of the following year is a leap year?
Answer: D
A year is a leap year if it is divisible by 4, except that a century year must also be divisible by 400.
All four are century years, so each must be divisible by 400.
\[ 2500 \div 400 = 6.25 \ \times, \quad 1700 \div 400 = 4.25 \ \times, \quad 1900 \div 400 = 4.75 \ \times \]
\[ 2400 \div 400 = 6 \ \checkmark \]
So 2400 is the leap year.
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The calendar for the year 2007 will be the same for the year
Answer: D
A calendar repeats once the accumulated odd days come back to zero. 2007 is an ordinary year, so count forward, giving each ordinary year 1 odd day and each leap year 2:
| Year | Odd days | Running total (mod 7) |
|---|---|---|
| 2007 | 1 | 1 |
| 2008 (leap) | 2 | 3 |
| 2009 | 1 | 4 |
| 2010 | 1 | 5 |
| 2011 | 1 | 6 |
| 2012 (leap) | 2 | 1 |
| 2013 | 1 | 2 |
| 2014 | 1 | 3 |
| 2015 | 1 | 4 |
| 2016 (leap) | 2 | 6 |
| 2017 | 1 | 0 |
The total returns to 0 after 2017, so the first year whose calendar matches 2007 is 2018. Both must also be non-leap for the match to hold, and 2018 is.
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On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
Answer: B
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday
S0, 8th Dec, 2006 is Friday.
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How many leap years do 300 years have?
Answer: C
Each century contributes 24 leap years, since the century year itself is skipped unless divisible by 400.
\[ 24 \times 3 = 72 \]
Only in a 400-year block does one century year qualify, giving 97 leap years in 400 rather than 96.
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The calendar for the year 2018 will be the same for the year
Answer: C
Now, the given year is 2018
We know that 2016 is a Leap year.
2016 2017 2018 2019 2020
LY 1st 2nd 3rd LY
Here 2018 is at 2 nd position after the Leap year.
According to rule ( b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.
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Which century year is a leap year?
Answer: C
A year is a leap year if it is divisible by 4, except that a century year must also be divisible by 400.
So 1600 is the leap century year here.
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On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Answer: C
The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
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If every seconds Saturday and all Sundays are holidays in a 30 days month beginning on Saturday, then how many working days are there in that month ? (Month starts from Saturday)
Answer: D
The month has 30 days and begins on a Saturday, so:
\[ \text{Saturdays: } 1, 8, 15, 22, 29 \]
\[ \text{Sundays: } 2, 9, 16, 23, 30 \]
All five Sundays are holidays. "Every second Saturday" means alternate Saturdays - the 8th and the 22nd:
\[ \text{holidays} = 5 + 2 = 7 \]
\[ \text{working days} = 30 - 7 = 23 \]
Treating only the single "second Saturday" as a holiday would leave 24 days.
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If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Answer: A
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
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If 4th december 1999 is Monday then what day is 3rd january 2000 ?
Answer: D
Here from 4th December 1999 to 3rd January 2000,
there is a difference of 30 days.
Number of odd days = 30/7 = 2 odd days
Then no. of odd days = 2 => tuesday and wednesday(from monday).
Hence on 3rd january it is wednesday.
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