Calendar Questions and Answers

Important Instructions

41.

What will be the day of the week on fifteenth 2010?

A.Sunday
B.Monday
C.Tuesday
D.Friday

Answer: A

fifteenth August,2010 =(2009 years+ Period from 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0.
Odd days in 400 years = 0.

9 year = (2 jump year +7 conventional years)
= (2*2+7*1) = 11 odd days= 4 odd days

Jan + feb + March + April + May + June + July + august
31+28+31+30+31+30+31+15 = 227 days =(32 weeks +3 days )
= 3 odd days

Aggregate no. of odd days = (0+0+4+3) =7
= 0 odd day

Given day is Sunday.

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42.

The calendar of the year 2024 can be used again in the year?

A.2030
B.2052
C.2048
D.2036

Answer: B

A calendar repeats when the accumulated odd days return to zero. 2024 is a leap year, and leap-year calendars repeat on a 28-year cycle:

\[ 2024 + 28 = 2052 \]

The cycle holds as long as no skipped century year intervenes, and none does between 2024 and 2052.

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43.

What was the day of the week on 28th May, 2006?

A.Thursday
B.Friday
C.Saturday
D.Sunday

Answer: D

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

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44.

Which of the following year is a leap year?

A.2500
B.1700
C.1900
D.2400

Answer: D

A year is a leap year if it is divisible by 4, except that a century year must also be divisible by 400.

All four are century years, so each must be divisible by 400.

\[ 2500 \div 400 = 6.25 \ \times, \quad 1700 \div 400 = 4.25 \ \times, \quad 1900 \div 400 = 4.75 \ \times \]

\[ 2400 \div 400 = 6 \ \checkmark \]

So 2400 is the leap year.

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45.

The calendar for the year 2007 will be the same for the year

A.2014
B.2016
C.2017
D.2018

Answer: D

A calendar repeats once the accumulated odd days come back to zero. 2007 is an ordinary year, so count forward, giving each ordinary year 1 odd day and each leap year 2:

Year	Odd days	Running total (mod 7)
2007	1	1
2008 (leap)	2	3
2009	1	4
2010	1	5
2011	1	6
2012 (leap)	2	1
2013	1	2
2014	1	3
2015	1	4
2016 (leap)	2	6
2017	1	0

The total returns to 0 after 2017, so the first year whose calendar matches 2007 is 2018. Both must also be non-leap for the match to hold, and 2018 is.