If 18 (9) 3 and 36 (30) 5, then what is the value of A in 19 (A) 18?
Answer: B
Correct answer: 57
The number in brackets is the product of the outer two divided by six: \( \tfrac{18\times3}{6} = 9 \) and \( \tfrac{36\times5}{6} = 30 \). So \[ A = \frac{19 \times 18}{6} = \mathbf{57} \]
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