Alphabet Test Questions and Answers

Q: Find out how many such pairs of letters are there in the given word each of which has as many letters between them in the word as in the English alphabet.I N C R E D I B L E

There are 8 such pairs.A pair qualifies when the gap between two letters in the word equals their gap in the alphabet. Checking every pair in I N C R E D I B L E (counting both forward and backward order in the alphabet) gives:I-E, I-D, I-B (the first I with E, D and B), N-I, C-E, E-D, E-B and D-B.For example, I and E are four places apart in the word (I N C R E) and four apart in the alphabet (E F G H I). That makes 8 pairs; the smaller options miss some of them.

Q: If 1st and 26th, 2nd and 25th, 3rd and 24th and so on letters of the English alphabet are paired, then which of the following pairs is correct ?

The correct pair is I R.When the 1st letter is paired with the 26th, the 2nd with the 25th and so on, the positions in every pair add up to 27. I is the 9th letter and R the 18th, and \(9 + 18 = 27\), so I pairs with R.The other pairs fail the test: H (8) and T (20) add to 28, J (10) and P (16) to 26, and F (6) and V (22) to 28. H actually pairs with S, J with Q, and F with U.

Q: If in each of the following words, each letter is changed to the next letter in the English alphabetical order, how many words thus formed will have NO vowel? END MAT JAR BED

Only one word has no vowel after the change.Move each letter to the next letter: END becomes FOE (contains O and E), MAT becomes NBU (contains U), JAR becomes KBS (no vowel) and BED becomes CFE (contains E). So only KBS has no vowel.Two, three and four would need more of the words to lose all their vowels, which does not happen.It is easiest to check each word separately. END has the vowel E in the original, and after shifting it becomes FOE, which has O and E. MAT becomes NBU, and U is a vowel. BED becomes CFE, which ends with E. Only JAR, which becomes KBS, has no vowel left.

Q: If the letter 'B' is added to the beginning of each of the given words, which of them will form a meaningful English word? END MAT JAR BED

END only forms a meaningful word.Adding B in front gives BEND, BMAT, BJAR and BBED. Only BEND is an English word. The others are not words.So MAT only, both END and MAT, and both JAR and BED are all wrong.Test each word one at a time: BEND is a common English word meaning to curve, BMAT, BJAR and BBED are not words at all. Since just one of the four forms a word, the answer is END only, and any option naming MAT, JAR or BED fails.

Important Instructions

Find out how many such pairs of letters are there in the given word each of which has as many letters between them in the word as in the English alphabet.

I N C R E D I B L E

Exam Year(s)

CBSE Assistant Secretary - 2024,

Answer: C

There are 8 such pairs.

A pair qualifies when the gap between two letters in the word equals their gap in the alphabet. Checking every pair in I N C R E D I B L E (counting both forward and backward order in the alphabet) gives:

I-E, I-D, I-B (the first I with E, D and B), N-I, C-E, E-D, E-B and D-B.

For example, I and E are four places apart in the word (I N C R E) and four apart in the alphabet (E F G H I). That makes 8 pairs; the smaller options miss some of them.

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If 1st and 26^th, 2nd and 25^th, 3rd and 24^th and so on letters of the English alphabet are paired, then which of the following pairs is correct ?

A.H T
B.J P
C.F V
D.I R

Exam Year(s)

CBSE Assistant Secretary - 2024,

Answer: D

The correct pair is I R.

When the 1st letter is paired with the 26th, the 2nd with the 25th and so on, the positions in every pair add up to 27. I is the 9th letter and R the 18th, and \(9 + 18 = 27\), so I pairs with R.

The other pairs fail the test: H (8) and T (20) add to 28, J (10) and P (16) to 26, and F (6) and V (22) to 28. H actually pairs with S, J with Q, and F with U.

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Study the following arrangements carefully and answer the questions given below:

F G + @ - T U V @ A C G 1 M N 3 4 K L 5 6 @ # S 1 # 2

How many such numbers are there in the given series which are immediately followed by a particular symbol?

Exam Year(s)

DSSSB PGT - 2023,

Answer: D

Look at each number in the series: F G + @ - T U V @ A C G 1 M N 3 4 K L 5 6 @ # S 1 # 2. The number 1 in 'G 1 M' is followed by the letter M, so it does not count. The number 3 is followed by 4, a number, and 4 is followed by K, a letter. The number 5 is followed by 6, a number, and 6 is followed by the symbol @, so 6 counts. The number 1 after S is followed by the symbol #, so it counts. The last number, 2, has nothing after it. So two numbers are immediately followed by a symbol, and the answer is 2, option D.

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If the letters in the word ‘PALINDRONE’ are rearranged as they appear in the English alphabet, then the position of how many letters will remain unchanged after the rearrangement?

Exam Year(s)

DSSSB - 2023,

Answer: D

Arrange the letters of PALINDRONE alphabetically: A, D, E, I, L, N, N, O, P, R. Compare each place with the original word P, A, L, I, N, D, R, O, N, E. The 4th place is I in both, and the 8th place is O in both. No other place matches, because the 1st is P against A, the 2nd A against D, the 3rd L against E, the 5th N against L, the 6th D against N, the 7th R against N, the 9th N against P and the 10th E against R. So 2 letters keep their positions, option (D). The options 1, 3 and 0 miss or add a match.

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Refer to the following letter string and answer the question.

(Left) E U V Y F S C B A B C W U E A X F I M D K T (Right)

How many such vowels are there each of which is immediately preceded by a consonant?

Exam Year(s)

DSSSB - 2023,

Answer: B

Read the string E U V Y F S C B A B C W U E A X F I M D K T from the left and look at each vowel with the letter just before it. The first E has nothing before it, U follows E, which is a vowel, and so does not count. The A after B counts, because B is a consonant. The U after W counts. The E after U does not count, and the A after E does not count. The I after F counts. So three vowels are immediately preceded by a consonant, option (B). The counts 2, 4 and 5 miss one of them or include a vowel that follows another vowel.

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How many such pairs of letters are there in the word ‘RAPIDLY’ each of which has as many letters between them as in the English alphabetical series in both forward and backward direction?

Exam Year(s)

DSSSB - 2023,

Answer: B

Number the letters of RAPIDLY as R1, A2, P3, I4, D5, L6, Y7 and test pairs for the same number of letters between them in the word as in the alphabet. R and P have one letter between them in the word (A), and in the alphabet only Q lies between P and R, so they fit. A and D have two letters between them in the word (P and I), and in the alphabet B and C lie between A and D, so they fit. Every other pair fails, for instance R and Y have five letters between them in the word but six in the alphabet. So 2 pairs fit, option (B); 0, 1 and 3 miscount them.

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If the first half of the English alphabet series is written in reverse order and no change is made in the second half, which letter is 11th to the left of the letter that is 7th from the end?

Exam Year(s)

DSSSB - 2023,

Answer: D

Writing the first half of the alphabet in reverse order and leaving the second half unchanged gives the series: M L K J I H G F E D C B A N O P Q R S T U V W X Y Z. In this series, counting from the end, the 7th letter is T (Z, Y, X, W, V, U, T).

T is at position 20 from the left. The 11th letter to its left is at position 20 - 11 = 9, and the 9th letter of the new series is E. So the answer is E. The letters R, F and I are the letters at other positions in the series, which come from miscounting the 7th letter from the end or the 11 places.

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If in each of the following words, each letter is changed to the next letter in the English alphabetical order, how many words thus formed will have NO vowel? END MAT JAR BED

A.One
B.Two
C.Three
D.Four

Exam Year(s)

DSSSB - 2023,

Answer: A

Only one word has no vowel after the change.

Move each letter to the next letter: END becomes FOE (contains O and E), MAT becomes NBU (contains U), JAR becomes KBS (no vowel) and BED becomes CFE (contains E). So only KBS has no vowel.

Two, three and four would need more of the words to lose all their vowels, which does not happen.

It is easiest to check each word separately. END has the vowel E in the original, and after shifting it becomes FOE, which has O and E. MAT becomes NBU, and U is a vowel. BED becomes CFE, which ends with E. Only JAR, which becomes KBS, has no vowel left.

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If the letter 'B' is added to the beginning of each of the given words, which of them will form a meaningful English word? END MAT JAR BED

A.END only
B.MAT only
C.Both END and MAT
D.Both JAR and BED

Exam Year(s)

DSSSB - 2023,

Answer: A

END only forms a meaningful word.

Adding B in front gives BEND, BMAT, BJAR and BBED. Only BEND is an English word. The others are not words.

So MAT only, both END and MAT, and both JAR and BED are all wrong.

Test each word one at a time: BEND is a common English word meaning to curve, BMAT, BJAR and BBED are not words at all. Since just one of the four forms a word, the answer is END only, and any option naming MAT, JAR or BED fails.

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10.

If a man reaches the 15^th letter from beginning and the 14^th letter from the end in the English alphabet, what would be the letter exactly between these two letters?

Exam Year(s)

DSSSB TGT - 2023,

Answer: A

The letter exactly between them is N. The 15th letter from the beginning is O. The 14th letter from the end is the \(27 - 14 = 13\)th from the beginning, which is M. M is the 13th and O the 15th, so the letter exactly between them is the 14th, N. L is before M and so lies outside the pair, and O is one of the two end letters, so neither can be between them. M likewise is itself one of the two letters. In alphabetical order the 13th, 14th and 15th letters are M, N and O, so the letter between the 13th (M) and the 15th (O) is the 14th, N.

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