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Group Theory in Physics Questions and Answers

1.

What is the maximum number of free independent real parameters specifying an \(n\)-dimensional orthogonal matrix?

Exam Year(s)

GATE Physics - 2022,

Answer: C

The number is \(\frac{n(n - 1)}{2}\).

An \(n \times n\) real matrix has \(n^{2}\) entries. Orthogonality, \(O^{T}O = I\), imposes one condition for each entry of the symmetric matrix \(O^{T}O\), that is \(\frac{n(n + 1)}{2}\) independent conditions. The free parameters are

\[ n^{2} - \frac{n(n + 1)}{2} = \frac{n(n - 1)}{2} \]

For \(n = 2\) this gives 1 (a rotation angle) and for \(n = 3\) it gives 3 (the Euler angles), as expected. \(\frac{n(n + 1)}{2}\) is the number of constraints, not of free parameters, and \((n - 1)^{2}\) and \(n(n - 2)\) fail the \(n = 2\) and \(n = 3\) checks.

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Answer: D

The set that forms a group is \(\begin{pmatrix} \alpha & \beta \\ -\beta^{*} & \alpha^{*} \end{pmatrix}\) with \(|\alpha|^{2} + |\beta|^{2} = 1\).

These are exactly the matrices of SU(2): unitary with determinant \(|\alpha|^{2} + |\beta|^{2} = 1\). The product of two such matrices has the same form, the identity is included (\(\alpha = 1, \beta = 0\)), and each has an inverse, its conjugate transpose, of the same form.

The others fail: the first has determinant 0, so no inverse. In the second, the product of two such matrices does not keep 1s on the diagonal, so the set is not closed. In the third, the determinant \(\alpha\beta^{*} - \alpha^{*}\beta\) is zero when \(\alpha\beta^{*}\) is real, so again there is no inverse.

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