When a body falls in viscous medium, its velocity first increases and finally becomes constant. The constant velocity is called
Answer: D
This constant speed is the terminal velocity.
The body accelerates until the viscous drag and buoyancy together balance the weight, after which the net force is zero. For a sphere obeying Stokes' law, \[v_t = \frac{2r^2(\rho - \sigma)g}{9\eta}\]
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