The peak of 1 h unit hydrograph in m3s−1 for the watershed and its time of occurrence in h, respectively are
GATE AG - 2012,
Answer: C
The 1-h unit hydrograph peaks at 8 m3 s−1 at 2 h.
The direct runoff hydrograph is 2 cm times the unit hydrograph plus 3 cm times the unit hydrograph lagged by 1 hour. Solve for the ordinates u in turn (direct runoff 0, 6, 25, 36, 26, 12, 0):
\[ \begin{aligned} 6 &= 2u_{1} \Rightarrow u_{1} = 3 \\ 25 &= 2u_{2} + 3u_{1} \Rightarrow u_{2} = 8 \\ 36 &= 2u_{3} + 3u_{2} \Rightarrow u_{3} = 6 \\ 26 &= 2u_{4} + 3u_{3} \Rightarrow u_{4} = 4 \end{aligned} \]
The ordinates 0, 3, 8, 6, 4, 0 give a peak of 8 at t = 2 h. Peaks at 1 h come from reading the first rise alone, and a peak of 7 or 9 does not satisfy the convolution.
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