If 5 mA current is drawn from the voltage source in the circuit connected with two resistors each of 2.4 kΩ and four ideal diodes, then the source voltage is

KEAM - 2026,
Answer: A
The source voltage is 12 V.
In the upper branch the two diodes face opposite ways, so one of them is always reverse-biased and no current flows there. In the lower branch both ideal diodes are forward-biased and have zero resistance, so all 5 mA flows through the lower 2.4 kΩ resistor.
\[ V = 5 \times 10^{-3} \times 2.4 \times 10^{3} = 12\ \text{V} \]
6 V treats the two resistors as being in parallel (1.2 kΩ), and 24 V as being in series (4.8 kΩ); both ignore the blocked upper branch.
Please log in or register to report this question.