Functions Questions and Answers

Q: Which of the following is an external variable? int func (int a) { int b; return b; } int main() { int c; func (c); } int d;

Correct answer: dd is declared at file scope, so it is the external variable - even though it appears at the end of the file, which merely limits how much of the file can see it. a is a parameter, and b and c are locals; all three are automatic.

Q: What is the output of this C code? void main() { m(); void m() { printf("hi"); } }

Correct answer: Compile time errorm is defined inside main, which standard C forbids - and it is also called before its definition is reached. The compiler rejects the program.

Q: What is the output of this C code? void foo(); int main() { void foo(int); foo(); return 0; } void foo() { printf("2 "); }

Correct answer: Compile time errorHere the two disagree. The declaration in scope says void foo(int), so foo() is called with too few arguments; and the definition, void foo(), conflicts with it as well. Either fault alone is enough for the compiler to reject the program.

111.

Which of the following is an external variable?

int func (int a)
    {
        int b;
        return b;
    }
    int main()
    {
        int c;
        func (c);
    }
    int d;

Answer: D

Correct answer: d

d is declared at file scope, so it is the external variable - even though it appears at the end of the file, which merely limits how much of the file can see it. a is a parameter, and b and c are locals; all three are automatic.

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112.

What is the output of this C code?

void main()
    {
        m();
        void m()
        {
            printf("hi");
        }
    }

A.hi
B.Compile time error
C.Nothing
D.Varies

Answer: B

Correct answer: Compile time error

m is defined inside main, which standard C forbids - and it is also called before its definition is reached. The compiler rejects the program.

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113.

What is the output of this C code?

void foo();
int main()
{
void foo(int);
foo();
return 0;
}
void foo()
{
printf("2 ");
}

A.2
B.Compile time error
C.Depends on the compiler
D.Depends on the standard

Answer: B

Correct answer: Compile time error

Here the two disagree. The declaration in scope says void foo(int), so foo() is called with too few arguments; and the definition, void foo(), conflicts with it as well. Either fault alone is enough for the compiler to reject the program.

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114.

Which of the following is not accepted in C?

A.static a = 10; //static as
B.static int func (int); //parameter as static
C.static static int a; //a static variable prefixed with static
D.All of the mentioned

Answer: C

Correct answer: static static int a; //a static variable prefixed with static

A storage class specifier may appear only once in a declaration, so static static is rejected. The other two are legal: static a = 10; relies on the old implicit int, and static int func(int); declares a function with internal linkage.

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115.

Can we use a function as a parameter of another function? [ Eg: void wow(int func()) ]

A.Yes, and we can use the function value conveniently
B.Yes, but we call the function again to get the value, not as convenient as in using variable
C.No, C does not support it.
D.This case is compiler dependent

Answer: C

Correct answer: Yes, but we call the function again to get the value, not as convenient as in using variable

C does allow it: a parameter written as a function is adjusted to a pointer to that function, so void wow(int func()) means void wow(int (*func)()). But what is passed is the function itself, not a value - so inside wow you must call it to obtain anything, which is less convenient than passing the value. This is the mechanism behind callbacks, such as the comparison function given to qsort.

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