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Reasoning Under Uncertainty Questions and Answers

111.

Consider a fuzzy set A defined on the interval X = [0, 10] of integers by the membership Junction

\(\mu_A(x) = \frac{x}{x+2}\)

Then the \(\alpha\) cut corresponding to \(\alpha\) = 0.5 will be

Exam Year(s)

UGC NET - 2012,

Answer: C

The alpha cut of a fuzzy set contains the elements whose membership is at least alpha. Here the membership is \(\mu_A(x) = x/(x+2)\) and alpha = 0.5, so the condition is

\[ \frac{x}{x+2} \ge 0.5 \]\[ x \ge 0.5x + 1 \Rightarrow x \ge 2 \]

The values of x in the interval [0, 10] that satisfy this are 2, 3, ..., 10. For x = 1 the membership is 1/3, which is less than 0.5, and for x = 0 it is 0, so these are left out. The set is {2, 3, 4, 5, 6, 7, 8, 9, 10}, the third option. The empty set would hold only if no value reached 0.5.

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112.

If A and B are two fuzzy sets with membership functions

\(\mu_{A}(x) = \{0.2, 0.5, 0.6, 0.1, 0.9\}\)
\(\mu_{B}(x) = \{0.1, 0.5, 0.2, 0.7, 0.8\}\)

Then the value of \(\mu_{A \cap B}\) will be

Exam Year(s)

UGC NET - 2013,

Answer: D

The intersection of two fuzzy sets takes the minimum of the membership values element by element, \(\mu_{A \cap B}(x) = \min(\mu_{A}(x), \mu_{B}(x))\). The pairs are (0.2, 0.1), (0.5, 0.5), (0.6, 0.2), (0.1, 0.7) and (0.9, 0.8), whose minima are 0.1, 0.5, 0.2, 0.1 and 0.8.

So the result is {0.1, 0.5, 0.2, 0.1, 0.8}. Option A takes maxima, which is the union, and options B and C each take a wrong value at one or more positions.

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113.

The height h(A) of a fuzzy set A is defined as

\(h(A) = \sup_{x \in A} A(x)\)

Then the fuzzy set A is called normal when

Exam Year(s)

UGC NET - 2013,

Answer: C

A fuzzy set is called normal when its height h(A) equals 1, that is, at least one element has full membership. The height is the supremum of the membership values, so a set with h(A) = 1 reaches the maximum possible grade.

If h(A) is 0, or less than 0 or less than 1, no element has full membership, so the set is sub-normal. A value below 0 is impossible for a membership function, which lies in the interval from 0 to 1.

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114.

A fuzzy set A on R is ________ iff \(A(\lambda x_{1} + (1 - \lambda)x_{2}) \ge \min [A(x_{1}), A(x_{2})]\) for all \(x_{1}, x_{2} \in R\) and all \(\lambda \in [0, 1]\), where min denotes the minimum operator.

Exam Year(s)

UGC NET - 2013,

Answer: C

A fuzzy set A on R is convex if and only if \(A(\lambda x_{1} + (1 - \lambda)x_{2}) \ge \min [A(x_{1}), A(x_{2})]\) for all \(x_{1}, x_{2}\) and all \(\lambda \in [0, 1]\), which is option (C). This says that the membership of any point between two points is at least the smaller of their memberships.

The support is the set of points with non-zero membership, an \(\alpha\)-cut is the set with membership at least \(\alpha\), and concave is not the term for this property. So (A), (B) and (D) are wrong.

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115.

If A and B are two fuzzy sets with membership functions
\(\mu_{A}(x) = \{0.6, 0.5, 0.1, 0.7, 0.8\}\)
\(\mu_{B}(x) = \{0.9, 0.2, 0.6, 0.8, 0.5\}\)
Then the value of \(\mu_{\overline{A \cup B}}(x)\) will be

Exam Year(s)

UGC NET - 2013,

Answer: C

The membership of the complement of \(A \cup B\) is found by taking the maximum of the two memberships point by point, and then subtracting from 1:

\[ \mu_{A \cup B} = \{0.9, 0.5, 0.6, 0.8, 0.8\} \]

\[ 1 - \mu_{A \cup B} = \{0.1, 0.5, 0.4, 0.2, 0.2\} \]

This is option (C). Option (A) is the union itself, option (B) is the point by point minimum, which is the intersection, and option (D) differs in the last value, which would need a membership of 0.7.

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