Alphabet Test Questions and Answers

Q: What is the 207th element from right of the sequence: Z, Y, Y, X, X, X, W, W, W, W, V, V, V, V, V, ..., A ?

The 207th element from the right is J.Each letter appears as many times as its position from A: Z once, Y twice, and so on, down to A 26 times. Counting from the right means starting with the A block (26 letters), then B (25), C (24) and so on.\[ \begin{aligned} A{:}\ 26,\ B{:}\ 51,\ C{:}\ 75,\ D{:}\ 98 \\ E{:}\ 120,\ F{:}\ 141,\ G{:}\ 161 \\ H{:}\ 180,\ I{:}\ 198,\ J{:}\ 215 \end{aligned} \]The running totals show the I block ends at position 198 and the J block (17 letters) covers 199 to 215, so position 207 is a J. H and I are reached by stopping one or two blocks early.

Q: In the series AABABCABCDABCDEABCDEF..., which letter appears at the 261st place?

The 261st letter is H.The series is built in blocks: A, AB, ABC, ABCD, and so on, block n having n letters. After n blocks the length is \(n(n+1)/2\).\[ \begin{aligned} \frac{22 \times 23}{2} &= 253 \\ 261 - 253 &= 8 \end{aligned} \]The first 22 blocks fill 253 places, so place 261 is the 8th letter of block 23, which is H. G is an off-by-one from counting 7 places, and D and L come from miscounting the completed blocks.

Q: Which letter will be 9th from the right of 15th letter from the left in a forward alphabet series?

The letter is X.The 15th letter from the left of the alphabet is O. Counting 9 letters to its right:\[ 15 + 9 = 24\text{th letter} = X \]R, S and T are the 18th, 19th and 20th letters, which would be 3, 4 and 5 places to the right of O.

Q: Which of the following words cannot be formed using the letters of the word 'TRAINING' ?

The word that cannot be formed is KING.TRAINING contains the letters T, R, A, I (twice), N (twice) and G. GAIN uses G, A, I, N; RAIN uses R, A, I, N; RING uses R, I, N, G, all of which are available.KING needs the letter K, which does not occur in TRAINING, so it cannot be formed however the other letters are arranged.

Q: Which one of the following words cannot be formed by using the letters of the word "Educational" ?

The word that cannot be formed is NATIONAL.The letters of 'Educational' are E, D, U, C, A, T, I, O, N, A, L: the word has two As but only one N. NATIONAL needs two Ns (N-A-T-I-O-N-A-L), so it cannot be formed.LION uses L, I, O, N; DEAN uses D, E, A, N; and NEAT uses N, E, A, T. Each letter is available in 'Educational' as many times as needed.

Q: Choose the correct option to complete the alphabet letter series__ ABA __CABC __ DCBA __ BAB __ A

The missing letters are ABDCA.Filling the five blanks in order givesA ABA B CABC D DCBA C BAB A Awhich reads as A, AB, ABC, ABCD, DCBA, CBA, BA, A: the alphabet is built up one letter at a time to ABCD and then taken down again in reverse.Each of the other options breaks this pattern at its first blank or second blank; for instance BCADC would make the series start BABA, which fits no rule.

Q: How many such pairs of letters are there in the word SINGAPORE each of which has as many letters between them in the word as in the English alphabets ?

There are four such pairs, so the answer is More than three.A pair qualifies when the number of letters between them in the word equals the number between them in the alphabet. In SINGAPORE (S I N G A P O R E):I and G: one letter (N) between them in the word, one (H) in the alphabet.A and E: three letters (P, O, R) in the word, three (B, C, D) in the alphabet.P and O: adjacent in the word and in the alphabet.P and R: one letter (O) in the word, one (Q) in the alphabet.Counting only pairs that run in alphabetical order in both gives two (A-E and P-R), but the standard method counts pairs in either direction, which makes four, more than three.

Q: Which letter in the word CYBERNETICS occupies the same position as it does in the English alphabet ?

The letter is I.Number the letters of CYBERNETICS: C1, Y2, B3, E4, R5, N6, E7, T8, I9, C10, S11. The letter I is ninth in the word, and I is also the ninth letter of the alphabet.C stands 1st and 10th in the word but is the 3rd letter of the alphabet. E is 4th and 7th in the word but 5th in the alphabet, and T is 8th in the word but 20th in the alphabet.No other letter of CYBERNETICS stands where it does in the alphabet, so I is the only possible answer.

Important Instructions

11.

Study the following (English alphabetical) series and answer the question that follows.

ABCDEFGHIJKLMNOPQRSTUVWXYZ

If the 2^nd, 5^th, 12^th, 13^th, 15^th, 16^th and 18^th letters from the series are chosen to form a meaningful word, which letter will come in the middle of that word? Each letter must be used and only once.

Exam Year(s)

DSSSB TGT - 2023,

Answer: C

The middle letter is B. The letters at the given places are: 2nd B, 5th E, 12th L, 13th M, 15th O, 16th P and 18th R. These seven letters can be arranged into the meaningful word PROBLEM, in which the fourth letter, the middle one of seven, is B. E, O and L are all in the word, but they sit at the 6th, 3rd and 5th places of PROBLEM, not in the middle, so they are not the answer. As a check, P-R-O-B-L-E-M uses exactly the seven chosen letters once each, and a seven-letter word has its fourth letter in the middle, which is B.

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12.

What is the 207^th element from right of the sequence: Z, Y, Y, X, X, X, W, W, W, W, V, V, V, V, V, ..., A ?

Exam Year(s)

Haryana Civil Services - 2026, HPSC - 2026,

Answer: C

The 207th element from the right is J.

Each letter appears as many times as its position from A: Z once, Y twice, and so on, down to A 26 times. Counting from the right means starting with the A block (26 letters), then B (25), C (24) and so on.

\[ \begin{aligned} A{:}\ 26,\ B{:}\ 51,\ C{:}\ 75,\ D{:}\ 98 \\ E{:}\ 120,\ F{:}\ 141,\ G{:}\ 161 \\ H{:}\ 180,\ I{:}\ 198,\ J{:}\ 215 \end{aligned} \]

The running totals show the I block ends at position 198 and the J block (17 letters) covers 199 to 215, so position 207 is a J. H and I are reached by stopping one or two blocks early.

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13.

In the series AABABCABCDABCDEABCDEF..., which letter appears at the 261^st place?

Exam Year(s)

Haryana Civil Services - 2026, HPSC - 2026,

Answer: C

The 261st letter is H.

The series is built in blocks: A, AB, ABC, ABCD, and so on, block n having n letters. After n blocks the length is \(n(n+1)/2\).

\[ \begin{aligned} \frac{22 \times 23}{2} &= 253 \\ 261 - 253 &= 8 \end{aligned} \]

The first 22 blocks fill 253 places, so place 261 is the 8th letter of block 23, which is H. G is an off-by-one from counting 7 places, and D and L come from miscounting the completed blocks.

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14.

Which letter will be 9th from the right of 15th letter from the left in a forward alphabet series?

Exam Year(s)

ISRO Assistant - 2023,

Answer: D

The letter is X.

The 15th letter from the left of the alphabet is O. Counting 9 letters to its right:

\[ 15 + 9 = 24\text{th letter} = X \]

R, S and T are the 18th, 19th and 20th letters, which would be 3, 4 and 5 places to the right of O.

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15.

Which of the following words cannot be formed using the letters of the word 'TRAINING' ?

A.GAIN
B.RAIN
C.RING
D.KING

Exam Year(s)

MPPSC State Service - 2024, MPPSC Forest Service - 2024,

Answer: D

The word that cannot be formed is KING.

TRAINING contains the letters T, R, A, I (twice), N (twice) and G. GAIN uses G, A, I, N; RAIN uses R, A, I, N; RING uses R, I, N, G, all of which are available.

KING needs the letter K, which does not occur in TRAINING, so it cannot be formed however the other letters are arranged.

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16.

Which one of the following words cannot be formed by using the letters of the word "Educational" ?

A.LION
B.NATIONAL
C.DEAN
D.NEAT

Exam Year(s)

MPPSC State Service - 2023, MPPSC Forest Service - 2023,

Answer: B

The word that cannot be formed is NATIONAL.

The letters of 'Educational' are E, D, U, C, A, T, I, O, N, A, L: the word has two As but only one N. NATIONAL needs two Ns (N-A-T-I-O-N-A-L), so it cannot be formed.

LION uses L, I, O, N; DEAN uses D, E, A, N; and NEAT uses N, E, A, T. Each letter is available in 'Educational' as many times as needed.

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17.

Choose the correct option to complete the alphabet letter series

__ ABA __CABC __ DCBA __ BAB __ A

A.ABDCA
B.BCADC
C.ABCDD
D.CBDAA

Exam Year(s)

TNPSC Group 1 - 2017, TNPSC - 2017,

Answer: A

The missing letters are ABDCA.

Filling the five blanks in order gives

A ABA B CABC D DCBA C BAB A A

which reads as A, AB, ABC, ABCD, DCBA, CBA, BA, A: the alphabet is built up one letter at a time to ABCD and then taken down again in reverse.

Each of the other options breaks this pattern at its first blank or second blank; for instance BCADC would make the series start BABA, which fits no rule.

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18.

If \(A = Z = 1, B = Y = 2, C = X = 3, \ldots\) etc.

Which one is wrong?

A.\(M = N\)
B.\(M + N = L + O + A + Z\)
C.\(A + B + C = X + Y + Z\)
D.\(E, G, J\) are prime numbers

Exam Year(s)

TNPSC Group 1 - 2024, TNPSC - 2024,

Answer: D

With A = Z = 1, B = Y = 2 and so on, each letter takes the smaller of its place and its place from the end. M and N both have the value 13, so M = N is true, and M + N = 26 = L + O + A + Z = 12 + 12 + 1 + 1.

A + B + C = 6 = X + Y + Z is true. For E, G and J the values are 5, 7 and 10, and 10 is not prime, so the last statement is wrong, option D.

The code A to M gives the values 1 to 13 and N to Z the values 13 down to 1. So E, G and J have the values 5, 7 and 10, and of these only 5 and 7 are prime. Statement D is therefore wrong, and the three other statements are right.

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19.

How many such pairs of letters are there in the word SINGAPORE each of which has as many letters between them in the word as in the English alphabets ?

A.One
B.Two
C.Three
D.More than three

Exam Year(s)

Tripura Public Service Commission - 2025,

Answer: D

There are four such pairs, so the answer is More than three.

A pair qualifies when the number of letters between them in the word equals the number between them in the alphabet. In SINGAPORE (S I N G A P O R E):

I and G: one letter (N) between them in the word, one (H) in the alphabet.
A and E: three letters (P, O, R) in the word, three (B, C, D) in the alphabet.
P and O: adjacent in the word and in the alphabet.
P and R: one letter (O) in the word, one (Q) in the alphabet.

Counting only pairs that run in alphabetical order in both gives two (A-E and P-R), but the standard method counts pairs in either direction, which makes four, more than three.

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20.

Which letter in the word CYBERNETICS occupies the same position as it does in the English alphabet ?

Exam Year(s)

Tripura Public Service Commission - 2019,

Answer: C

The letter is I.

Number the letters of CYBERNETICS: C1, Y2, B3, E4, R5, N6, E7, T8, I9, C10, S11. The letter I is ninth in the word, and I is also the ninth letter of the alphabet.

C stands 1st and 10th in the word but is the 3rd letter of the alphabet. E is 4th and 7th in the word but 5th in the alphabet, and T is 8th in the word but 20th in the alphabet.

No other letter of CYBERNETICS stands where it does in the alphabet, so I is the only possible answer.

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