A carrier of \( 100 \ \mathrm{V} \) peak is modulated to an index of \( 0.4 \). The envelope maximum is
Answer: A
The envelope reaches the carrier plus the message amplitude:
\[ V_{max} = 100(1+0.4) = 140 \ \mathrm{V} \]
so 140 volts, with a minimum of 60 volts. 104 V would follow from adding four per cent rather than forty. 40 V is the message amplitude alone. 160 V corresponds to an index of 0.6. The peak envelope voltage is what sizes the output devices and the antenna insulation, so it is a design figure rather than a merely academic one, and it grows to twice the carrier at full modulation.
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