Control Instructions Questions and Answers

Q: What will be the output of the program? #include <stdio.h> int main() { int i = 1; switch(i) { printf("Hello\n"); case 1: printf("Hi\n"); break; case 2: printf("\nBye\n"); break; } return 0; }

Correct answer: HiA switch jumps directly to a matching label, so the printf("Hello") written before any case is unreachable. i is 1, so control lands on case 1, prints Hi, and the break ends the switch.

Q: When 1 is entered, The output of the code below is? #include <stdio.h> void main() { int ch; printf("enter a value btw 1 to 2:"); scanf("%d", &ch); switch (ch, ch + 1) { case 1: printf("1\n"); break; case 2: printf("2"); break; } }

Correct answer: 2The controlling expression uses the comma operator: ch, ch + 1 evaluates ch, discards it, and yields ch + 1. With 1 entered, the switch is therefore performed on 2, so case 2 runs and prints 2.

Q: Which of the following statements are correct about the below program? #include <stdio.h> int main() { int i = 0; i++; if(i <= 5) { printf("IndiaBIX\n"); exit(0); main(); } return 0; }

Correct answer: The program prints 'IndiaBIX' one timeexit(0) terminates the program immediately. The recursive main() call written after it is never reached, so the message is printed exactly once. (Calling main recursively is legal in C, which is why the last option is wrong - it just never happens here.)

Q: Can we use a switch statement to switch on strings?

Correct answer: NoA switch requires an integer controlling expression, and a string in C is an array of characters - in an expression, a pointer. Comparing strings means comparing their contents, which == does not do, so a chain of if (strcmp(s, "...") == 0) is the usual alternative. (Java added string switches; C has not.)

Q: How many lines of output does the following C code produce? #include <stdio.h> float i=2.0; float j=1.0; float sum = 0.0; main() { while (i/j > 0.001) { j+=j; sum=sum+(i/j); printf("%f\n", sum); } }

Correct answer: 11Each pass doubles j and prints, so the tested quantity \(i/j\) starts at 2 and halves every time: 2, 1, 0.5, 0.25, … The loop continues while it exceeds 0.001. Since \(2/2^{11} = 0.000977\) is the first value at or below the threshold, the test succeeds for \(j = 1, 2, 4, \ldots, 1024\) - eleven passes, and eleven lines.

Q: Point out the error, if any in the for loop. #include <stdio.h> int main() { int i=1; for(;;) { printf("%d\n", i++); if(i>10) break; } return 0; }

Correct answer: No errorfor(;;) is legal and idiomatic: all three clauses may be omitted, and an omitted condition is taken as true, giving an infinite loop. The two semicolons are required, since the header always has three parts. The loop here terminates properly through its break.

Q: What will be the output of the program? #include <stdio.h> int main() { char str[]="C-program"; int a = 5; printf(a >10?"Ps\n":"%s\n", str); return 0; }

Correct answer: C-programThe conditional operator chooses between the two format strings, not between two outputs. Since \(5 > 10\) is false, the format used is "%s\n", and str is the argument it consumes - so the program prints C-program. Had the condition been true, "Ps\n" would have been the format and str an unused extra argument.

Q: We want to test whether a value lies in the range 2 to 4 or 5 to 7. Can we do this using a switch?

Correct answer: YesA switch cannot test a range directly, but the ranges here are small and the values are integers, so each can be listed as its own label with fall-through:case 2: case 3: case 4: /* first range */ break;case 5: case 6: case 7: /* second range */ break;This works because a label with no statements falls through to the next. For a wide or non-integer range, an if is the only option.

Q: Which of the following errors would be reported by the compiler on compiling the program given below? #include <stdio.h> int main() { int a = 5; switch(a) { case 1: printf("First"); case 2: printf("Second"); case 3 + 2: printf("Third"); case 5: printf("Final"); break; } return 0; }

Correct answer: Duplicate case case 5:case 3 + 2 is perfectly legal - a label may be any constant expression, and the compiler evaluates it to 5. That is exactly the problem: it then collides with case 5, and duplicate labels are an error, since the jump would be ambiguous. Missing break statements are legal (they produce fall-through).

Q: Which keyword can be used for coming out of recursion?

Correct answer: returnRecursion is unwound by return: the base case returns instead of calling again, and each frame then returns in turn. break applies to loops and switches, not to function calls, and exit() would abandon the whole program rather than come back.

51.

What will be the output of the program?

#include <stdio.h>
int main()
{
    int i = 1;
    switch(i)
    {
        printf("Hello\n");
        case 1:
            printf("Hi\n");
            break;
        case 2:
            printf("\nBye\n");
            break;
    }
    return 0;
}

A.HelloHi
B.HelloBye
C.Hi
D.Bye

Answer: C

Correct answer: Hi

A switch jumps directly to a matching label, so the printf("Hello") written before any case is unreachable. i is 1, so control lands on case 1, prints Hi, and the break ends the switch.

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52.

When 1 is entered, The output of the code below is?

#include <stdio.h>
    void main()
    {
        int ch;
        printf("enter a value btw 1 to 2:");
        scanf("%d", &ch);
        switch (ch, ch + 1)
        {
        case 1:
            printf("1\n");
            break;
        case 2:
            printf("2");
            break;
        }
    }

A.1
B.2
C.3
D.Run time error

Answer: B

Correct answer: 2

The controlling expression uses the comma operator: ch, ch + 1 evaluates ch, discards it, and yields ch + 1. With 1 entered, the switch is therefore performed on 2, so case 2 runs and prints 2.

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53.

Which of the following statements are correct about the below program?

#include <stdio.h>
int main()
{
    int i = 0;
    i++;
    if(i <= 5)
    {
        printf("IndiaBIX\n");
        exit(0);
        main();
    }
    return 0;
}

A.The program prints 'IndiaBIX' 5 times
B.The program prints 'IndiaBIX' one time
C.The call to main() after exit() doesn't materialize.
D.The compiler reports an error since main() cannot call itself.

Answer: B

Correct answer: The program prints 'IndiaBIX' one time

exit(0) terminates the program immediately. The recursive main() call written after it is never reached, so the message is printed exactly once. (Calling main recursively is legal in C, which is why the last option is wrong - it just never happens here.)

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54.

Can we use a switch statement to switch on strings?

A.Yes
B.No

Answer: B

Correct answer: No

A switch requires an integer controlling expression, and a string in C is an array of characters - in an expression, a pointer. Comparing strings means comparing their contents, which == does not do, so a chain of if (strcmp(s, "...") == 0) is the usual alternative. (Java added string switches; C has not.)

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55.

How many lines of output does the following C code produce?

#include <stdio.h>
float i=2.0;
float j=1.0;
float sum = 0.0;
main()
{
    while (i/j > 0.001)
    {
        j+=j;
        sum=sum+(i/j);
        printf("%f\n", sum);
    }
}

A.8
B.9
C.10
D.11

Answer: D

Correct answer: 11

Each pass doubles j and prints, so the tested quantity \(i/j\) starts at 2 and halves every time: 2, 1, 0.5, 0.25, … The loop continues while it exceeds 0.001. Since \(2/2^{11} = 0.000977\) is the first value at or below the threshold, the test succeeds for \(j = 1, 2, 4, \ldots, 1024\) - eleven passes, and eleven lines.

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56.

Point out the error, if any in the for loop.

#include <stdio.h>
int main()
{
    int i=1;
    for(;;)
    {
        printf("%d\n", i++);
        if(i>10)
           break;
    }
    return 0;
}

A.There should be a condition in the for loop
B.The two semicolons should be dropped
C.The for loop should be replaced with while loop.
D.No error

Answer: D

Correct answer: No error

for(;;) is legal and idiomatic: all three clauses may be omitted, and an omitted condition is taken as true, giving an infinite loop. The two semicolons are required, since the header always has three parts. The loop here terminates properly through its break.

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57.

What will be the output of the program?

#include <stdio.h>
int main()
{
    char str[]="C-program";
    int a = 5;
    printf(a >10?"Ps\n":"%s\n", str);
    return 0;
}

A.C-program
B.Ps
C.Error
D.None of above

Answer: A

Correct answer: C-program

The conditional operator chooses between the two format strings, not between two outputs. Since \(5 > 10\) is false, the format used is "%s\n", and str is the argument it consumes - so the program prints C-program. Had the condition been true, "Ps\n" would have been the format and str an unused extra argument.

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58.

We want to test whether a value lies in the range 2 to 4 or 5 to 7. Can we do this using a switch?

A.Yes
B.No

Answer: A

Correct answer: Yes

A switch cannot test a range directly, but the ranges here are small and the values are integers, so each can be listed as its own label with fall-through:

case 2: case 3: case 4: /* first range */ break; case 5: case 6: case 7: /* second range */ break;

This works because a label with no statements falls through to the next. For a wide or non-integer range, an if is the only option.

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59.

Which of the following errors would be reported by the compiler on compiling the program given below?

#include <stdio.h>
int main()
{
    int a = 5;
    switch(a)
    {
    case 1:
    printf("First");

    case 2:
    printf("Second");

    case 3 + 2:
    printf("Third");

    case 5:
    printf("Final");
    break;

    }
    return 0;
}

A.There is no break statement in each case.
B.Expression as in case 3 + 2 is not allowed.
C.Duplicate case case 5:
D.No error will be reported

Answer: C

Correct answer: Duplicate case case 5:

case 3 + 2 is perfectly legal - a label may be any constant expression, and the compiler evaluates it to 5. That is exactly the problem: it then collides with case 5, and duplicate labels are an error, since the jump would be ambiguous. Missing break statements are legal (they produce fall-through).

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60.

Which keyword can be used for coming out of recursion?

A.return
B.break
C.exit
D.both A and B

Answer: A

Correct answer: return

Recursion is unwound by return: the base case returns instead of calling again, and each frame then returns in turn. break applies to loops and switches, not to function calls, and exit() would abandon the whole program rather than come back.

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