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Puzzle Test Questions and Answers

Important Instructions
Direction for [ Question No: 81 To 83 ] :

(i) In a family of six persons, there are people from three generations. Each person has separate profession and also they like different colours. There are two couples in the family.
(ii) Rohan is a CA and his wife neither is a doctor nor likes green colour.
(iii) Engineer likes red colour and his wife is a teacher.
(iv) Mohini is mother-in-law of Sunita and she likes orange colour.
(v) Vinod is grandfather of Tanmay and Tanmay, who is a principal, likes black colour.
(vi) Nanu is grand-daughter of Mohini and she likes blue colour. Nanu’s mother likes white colour.

81.

Which of the following is the correct pair of two couples ?

Answer: A

Mohini is mother-in-law of Sunita and grandmother of Nanu. Vinod is grandfather of Tanmay. So, Nanu and Tanmay represent third generation.
Mohini and Vinod form a couple and represent first generation.
Clearly, Roha and Sunita form the other couple and represent second generation.\
Rohan is a CA. Since engineer is married, so Vinod is an engineer and likes red colour.
Mohini is a teacher and likes orange colour.
Nanu likes blue colour.
Tanmay is a Principal and likes black colour.
Sunita, Nanu’s mother, likes white colour.
Clearly, Rohan likes green colour.
The two couples are Mohin-Vinod and Rohan-Sunita.

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82.

How many ladies are there in the family ?

Answer: B

Mohini is mother-in-law of Sunita and grandmother of Nanu. Vinod is grandfather of Tanmay. So, Nanu and Tanmay represent third generation.
Mohini and Vinod form a couple and represent first generation.
Clearly, Roha and Sunita form the other couple and represent second generation.\
Rohan is a CA. Since engineer is married, so Vinod is an engineer and likes red colour.
Mohini is a teacher and likes orange colour.
Nanu likes blue colour.
Tanmay is a Principal and likes black colour.
Sunita, Nanu’s mother, likes white colour.
Clearly, Rohan likes green colour.
There are three ladies in the family -- Mohin, Sunita and Nanu.

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83.

Which colour is liked by CA ?

Answer: A

Mohini is mother-in-law of Sunita and grandmother of Nanu. Vinod is grandfather of Tanmay. So, Nanu and Tanmay represent third generation.
Mohini and Vinod form a couple and represent first generation.
Clearly, Roha and Sunita form the other couple and represent second generation.\
Rohan is a CA. Since engineer is married, so Vinod is an engineer and likes red colour.
Mohini is a teacher and likes orange colour.
Nanu likes blue colour.
Tanmay is a Principal and likes black colour.
Sunita, Nanu’s mother, likes white colour.
Clearly, Rohan likes green colour.
Rohan is a CA and likes green colour.

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Direction for [ Question No: 84 To 87 ] :

(i) P, Q, R, S, T and U are six members of a group of which three are males and three are females.
(ii) There are two engineers, two lawyers, one teacher and one doctor in the group.
(iii) Q, T, P and R are two married couples and no person in this group has the same profession.
(iv) T, a teacher with blue dress, married a male lawyer with brown dress.
(v) Colour of the dresses of both the husbands and that of both the wives is the same.
(vi) Two persons have blue dress, two have brown and the remaining one each has black and green.
(vii) P is a male engineer whose sister S is also an engineer.
(viii) P is a male engineer whose sister S is also on engineer.
(ix) Q is a doctor.

84.

Which of the folowing is a group of female members ?

Answer: B

T is a female teacher with blue dress.
T married a lawyer. Now, P is an engineer and Q is a doctor. Clearly, T married R.
R is, thus, a male lawyer with brown dress.
One couple is RT. So, the other couple is PQ
P is a male engineer and has the same dress as R i.e., brown
Q is a female doctor and has the same dress as T i.e., blue.
S is the sister of P. S is a female engineer. Now, U remains. Since there are two lawyers, so U is a lawyer.
Both S and U have either black or green dress.

 

P

Q

R

S

T

U

Profession

Engineer

Doctor

Lawyer

Engineer

Teacher

Lawyer

Colour of Dress

Brown

Blue

Brown

Black or Green

Blue

Black or Green

Sex

Male

Female

Male

Female

Female

Male

Q, S and T are female members.

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85.

Which of the following is a pair of married ladies ?

Answer: C

T is a female teacher with blue dress.
T married a lawyer. Now, P is an engineer and Q is a doctor. Clearly, T married R.
R is, thus, a male lawyer with brown dress.
One couple is RT. So, the other couple is PQ
P is a male engineer and has the same dress as R i.e., brown
Q is a female doctor and has the same dress as T i.e., blue.
S is the sister of P. S is a female engineer. Now, U remains. Since there are two lawyers, so U is a lawyer.
Both S and U have either black or green dress.

 

P

Q

R

S

T

U

Profession

Engineer

Doctor

Lawyer

Engineer

Teacher

Lawyer

Colour of Dress

Brown

Blue

Brown

Black or Green

Blue

Black or Green

Sex

Male

Female

Male

Female

Female

Male

Q and T are married ladies.

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86.

Who is the wife of P ?

Answer: A

T is a female teacher with blue dress.
T married a lawyer. Now, P is an engineer and Q is a doctor. Clearly, T married R.
R is, thus, a male lawyer with brown dress.
One couple is RT. So, the other couple is PQ
P is a male engineer and has the same dress as R i.e., brown
Q is a female doctor and has the same dress as T i.e., blue.
S is the sister of P. S is a female engineer. Now, U remains. Since there are two lawyers, so U is a lawyer.
Both S and U have either black or green dress.

 

P

Q

R

S

T

U

Profession

Engineer

Doctor

Lawyer

Engineer

Teacher

Lawyer

Colour of Dress

Brown

Blue

Brown

Black or Green

Blue

Black or Green

Sex

Male

Female

Male

Female

Female

Male

Q is the wife of P.

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87.

What is the colour of U's dress ?

Answer: C

T is a female teacher with blue dress.
T married a lawyer. Now, P is an engineer and Q is a doctor. Clearly, T married R.
R is, thus, a male lawyer with brown dress.
One couple is RT. So, the other couple is PQ
P is a male engineer and has the same dress as R i.e., brown
Q is a female doctor and has the same dress as T i.e., blue.
S is the sister of P. S is a female engineer. Now, U remains. Since there are two lawyers, so U is a lawyer.
Both S and U have either black or green dress.

 

P

Q

R

S

T

U

Profession

Engineer

Doctor

Lawyer

Engineer

Teacher

Lawyer

Colour of Dress

Brown

Blue

Brown

Black or Green

Blue

Black or Green

Sex

Male

Female

Male

Female

Female

Male

U's dress is black or green in colour

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Direction for [ Question No: 88 To 90 ] :

(i) A, B, C, D, E and F are six members in a family in which there are two married couples.
(ii) D is brother of F. Both D and F are lighter than B.
(iii) B is mother of D and lighter than E.
(iv) C, a lady, is neither heaviest nor the lightest in the family.
(v) E is lighter than C.
(vi) The grandfather in the family is the heaviest.

88.

How is E related to F ?

Answer: C

In terms of weight, F < B, D < B, B < E, E < C. So, we have : D < F < B < E < C or F < D < B < E < C. C is not the heaviest. So, A is the heaviest. Thus, the sequence becomes : F < D < B < E < C < A or D < F < B < E < C < A.
D is the brother of F.
B is the mother of D and F.
A, being the heaviest, is the grandfather.
Now, C is a lady and so one couple is AC.
B is a female and so on cannot pair up with C. So, the other couples is BE.
E is the husband of B and B is the mother of F. So, E is the father of F.

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89.

Which of the following is a pair of married couples ?

Answer: D

In terms of weight, F < B, D < B, B < E, E < C. So, we have : D < F < B < E < C or F < D < B < E < C. C is not the heaviest. So, A is the heaviest. Thus, the sequence becomes : F < D < B < E < C < A or D < F < B < E < C < A.
D is the brother of F.
B is the mother of D and F.
A, being the heaviest, is the grandfather.
Now, C is a lady and so one couple is AC.
B is a female and so on cannot pair up with C. So, the other couples is BE.
AC and BE are the married couples. BE is one of them.

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90.

How many male members are there in the family ?

Answer: D

In terms of weight, F < B, D < B, B < E, E < C. So, we have : D < F < B < E < C or F < D < B < E < C. C is not the heaviest. So, A is the heaviest. Thus, the sequence becomes : F < D < B < E < C < A or D < F < B < E < C < A.
D is the brother of F.
B is the mother of D and F.
A, being the heaviest, is the grandfather.
Now, C is a lady and so one couple is AC.
B is a female and so on cannot pair up with C. So, the other couples is BE.
The sex of F is known.

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