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Direction Sense Test Questions and Answers

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61.

A man began to walk towards north. After walking 10 metre, he turned to his left and then walked 15 meter. Then he turned to his right and walked 5 meter. Again he turned to his right and walked 15 meter. Now, how far is he from his starting point ?

Exam Year(s)

Tripura Public Service Commission - 2019,

Answer: B

He is 15 meter from his starting point.

Track his position, taking north as up:

  • 10 m north: 10 m north of the start.
  • Left turn, so west, 15 m: 10 m north, 15 m west.
  • Right turn, so north again, 5 m: 15 m north, 15 m west.
  • Right turn, so east, 15 m: 15 m north, 0 m west.

The last move cancels the westward walk, so he ends up directly north of the start, 10 + 5 = 15 m away.

35 m is the total of the north and east-west legs without allowing for direction, and 10 m counts only the first leg.

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62.

Shyam goes 5 km. in the North from his school. Now, turning to the left, he goes to 10 km. and again turns to left and goes to 5 km. How far he is from his school and in which direction ?

Exam Year(s)

Tripura Public Service Commission - 2025,

Answer: C

Shyam is 10 km. West from school.

He walks 5 km north. Facing north, a left turn points him west, and he goes 10 km. Facing west, another left turn points him south, and he goes 5 km.

The 5 km south cancels the 5 km north, so he ends up directly west of the school, 10 km away. East would follow from right turns, and north or south would ignore that the two 5 km legs cancel.

Drawing the route on rough paper with north at the top is the safest way to solve direction questions.

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63.

A person starts from point A, walks 10 m north, turns right and walks 5 m, then turns right again and walks 10 m, and finally turns left and walks 5 m. How far and in which direction is the person from point A ?

Exam Year(s)

Tripura Public Service Commission - 2026,

Answer: C

The person is 10m East of point A.

Trace the walk: 10 m north; right turn means east, 5 m; right again means south, 10 m, back to the starting latitude; left turn from south means east, 5 m more.

The north and south legs cancel, and the two east legs add to 10 m, so the person ends 10 m due east of A. 5 m East counts only one of the eastward legs, and the West options take a left turn as west.

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64.

I am facing East ; I go 20 meters then turning to the left I go 20 meters, then after turning to the right I go 40 meters and then I go 40 meters to the right, now in which direction am I from my original position ?

Exam Year(s)

Tripura Public Service Commission - 2026,

Answer: B

The person ends up South-East of the start.

Starting facing east: 20 m east; turn left (north), 20 m; turn right (east again), 40 m; then turn right (south), 40 m.

East in total: \(20 + 40 = 60\) m. North-south: 20 m north, then 40 m south, leaving 20 m south. A point 60 m east and 20 m south of the start lies to the south-east. 'East' ignores the net southward movement, and the west options misread the turns.

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65.

Five trees A, B, C, D, E are situated close to each other. A is to the west of B, C is to the south of A, E is to the north of B and D is to the east of E. Then C is with respect to D in the direction

Exam Year(s)

Tripura Public Service Commission - 2019,

Answer: A

C is to the south-west of D.

Place B at the centre. A is west of B, and C is south of A, so C is to the south-west of B. E is north of B, and D is east of E, so D is to the north-east of B.

ED
AB
C

In this grid D is up and to the right of C, so C lies down and to the left of D: south-west. North-west would need C above D, and 'south-south' is not a direction.

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66.

One day A left home and cycled 10 km southwards, turned right and cycled 5 km and turned right and cycled 10 km and turned left and cycled 10 km. How many kilometers A will have to cycle to reach his home straight ?

Exam Year(s)

Tripura Public Service Commission - 2019,

Answer: D

The answer is 15 km.

Put home at the origin, with east to the right and north up. A cycles 10 km south to (0, -10). Facing south, a right turn faces west: 5 km takes A to (-5, -10). Facing west, a right turn faces north: 10 km takes A to (-5, 0). Facing north, a left turn faces west: 10 km takes A to (-15, 0).

A is now on the same east-west line as home, 15 km to its west, so the straight ride home is 15 km due east. The distances 20, 25 and 27 km do not match the path.

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67.

A person travels 18 Km due East, then 15 Km due South, after that 15 Km due North and finally 12 Km due West. How far is he from the starting point ?

Exam Year(s)

Tripura Public Service Commission - 2013,

Answer: A

He is 6 Km from the starting point.

Combine the movements along each direction separately:

\[ \begin{aligned} \text{East-West} &: 18 - 12 = 6\ \text{km East} \\ \text{North-South} &: 15 - 15 = 0 \end{aligned} \]

The southward and northward legs cancel, so he ends 6 km due east of the start. 33 km and 60 km add up distances travelled instead of the displacement, and 12 km is the length of the westward leg alone.

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68.

Kunal walks 10 km towards North. From there he walks 6 Km towards South. Then, he walks 3 Km towards east. How far and in which direction is he with reference to his starting point ?

Answer: D

Kunal moves from A 10 Km northwards upto B, then moves 6 Km southwards upto C, turns towards east and moves 3 km upto D.
Then AC = (AB-BC) = 4 Km

So Kunal distance from starting point A
\begin{aligned}
AD = \sqrt{AC^2 + CD^2} \\
= \sqrt{4^2+3^2} \\
= \sqrt{25} = 5
\end{aligned}

So AD is 5 Km also with reference to starting point Kunal's direction is North-East.

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69.

One morning after sunrise Nivedita and Niharika were talking to each other face to face at Dalphin crossing. If Niharika's shadow was exactly to the right of Nivedita, Which direction Niharika was facing?

Answer: A

In the morning sun rises in the East. Hence then any shadow falls in the West. Since Nikharia's shadow was exactly to the right of Nivedita. Hence Nikharia is facing towards North.

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70.

A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?

Answer: B

Correct answer: 13 km

The northward legs come to \( 2 + 3 = 5 \) km and the eastward to \( 10 + 2 = 12 \) km. By Pythagoras the distance is \[ \sqrt{5^2 + 12^2} = \sqrt{169} = \mathbf{13}\text{ km} \]

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