Two engines each of \( 120 \) kN thrust on an aircraft weighing \( 883 \) kN give a thrust-to-weight ratio of
Answer: C
Correct answer: 0.27
Both engines contribute, so
\[ \frac{T}{W} = \frac{2 \times 120}{883} = \frac{240}{883} \approx 0.27 \]A figure near 0.27 is typical of a twin-engined transport, which must be able to climb away on one engine after failure at the critical point. A fighter runs above 1.0 and can accelerate vertically; the difference in the number expresses the whole difference in mission.
Please log in or register to report this question.