Effluent of \( 240 \) m\(^3\) a day carries a biochemical oxygen demand of \( 1800 \) mg per litre. The daily organic load is
Answer: C
Correct answer: 432 kg
\[ 240\ \text{m}^3 = 240{,}000\ \text{L} \]\[ 240{,}000 \times 1800\ \text{mg/L} = 4.32 \times 10^{8}\ \text{mg} = 432\ \text{kg} \]The trap is the unit conversion: milligrams per litre times cubic metres gives grams, so a factor of 1000 is easily lost.
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