Machine-translated by Google. Questions are authored in English.
Top

Faults Folds and Joints Questions and Answers

Answer: C

Correct answer: the size of the blocks that may fall

Joint spacing, together with the number and orientation of the sets, fixes the dimensions of the blocks into which the rock mass is divided, and it is those blocks that fall out of a tunnel roof or slide from a wall. Support is designed around them: bolt length and spacing must be matched to the block size, and closely jointed ground needs mesh or shotcrete as well.

Please log in or register to report this question.

Answer: D

Correct answer: extent along its own plane

Persistence is how far a joint continues in its own plane - a metre or the whole height of a slope. It matters because a discontinuous joint requires intact rock bridges to be broken before a block can move, and those bridges may carry the whole stability of the slope, whereas a fully persistent joint offers a continuous failure surface. Spacing, aperture and roughness are the other joint properties, each described separately.

Please log in or register to report this question.

Answer: A

A plane daylighting in the face with a dip shallower than the slope provides a ready surface for a block to slide on. The same plane dipping into the face is harmless, which is why orientation matters more than strength.

Please log in or register to report this question.

Answer: B

Correct answer: crushed and often water-bearing material

A fault zone is a band of broken rock, breccia and gouge, of low strength and often high permeability, so the tunnel meets ground that will not stand unsupported and may deliver a sudden inflow of water. Where gouge has sealed one side of the zone, high pressure water may be held behind it and released without warning when the face breaks through - which is why fault zones are located in advance by probe drilling.

Please log in or register to report this question.

Answer: C

Correct answer: provide a leakage path and a plane of weakness

A fault crossing a dam abutment threatens the works twice over. Its crushed and often permeable material gives water a route around or beneath the structure, and the reservoir head drives flow along it; and it is a surface of low shear strength on which the abutment or the foundation may slide. Both are addressed before construction, by excavating and backfilling the zone and by grouting, and both have caused dam failures.

Please log in or register to report this question.

Answer: D

Correct answer: reduce permeability along the joints

Grout injected under pressure fills the open joints and reduces the permeability of the rock mass, which is what a grout curtain beneath a dam is for. It also stiffens the mass somewhat by knitting the blocks together, but the primary purpose is watertightness. It does not alter the intact strength of the rock material, which is a property of the mineral fabric, and it does not remove the joints.

Please log in or register to report this question.

Answer: A

Existing fractures give the shock wave surfaces to reflect from and give the gases paths to open up, so less explosive is needed per cubic metre. The same joints make the excavation less stable once it has been formed.

Please log in or register to report this question.

38.

A fault dipping at 65 degrees has a hade of

Answer: B

Correct answer: 25 degrees

Hade is measured from the vertical and dip from the horizontal, so the two are complementary:

\[ \text{hade} = 90^\circ - 65^\circ = 25^\circ \]

The steep fault has a small hade. Answering 65 degrees confuses the two conventions, which is exactly what the question tests.

Please log in or register to report this question.

39.

A fault with a slip of 50 m along a plane dipping at 30 degrees has a throw of

Answer: C

Correct answer: 25 m

The throw is the vertical component of the slip:

\[ \text{throw} = s\sin\delta = 50 \times \sin 30^\circ = 50 \times 0.5 = 25 \text{ m} \]

A shallow-dipping fault therefore gives a small throw for a large slip, which is why a thrust may carry rocks many kilometres horizontally while displacing them only modestly in the vertical.

Please log in or register to report this question.

40.

For that same fault the heave is about

Answer: D

Correct answer: 43 m

The heave is the horizontal component of the same slip:

\[ \text{heave} = s\cos\delta = 50 \times \cos 30^\circ = 50 \times 0.866 \approx 43 \text{ m} \]

Throw and heave are the two components of the net slip, and \( 25^2 + 43^2 \approx 50^2 \) as they must be. At 30 degrees the horizontal displacement is the larger of the two.

Please log in or register to report this question.

Loading…
Tags: Faults Folds and Joints Questions and Answers || Faults Folds and Joints MCQ Questions and Answers || Faults Folds and Joints GK Questions and Answers || Faults Folds and Joints GK MCQ Questions || Faults Folds and Joints Multiple Choice Questions and Answers || Faults Folds and Joints GK || GK on Faults Folds and Joints || Engineering Geology Questions and Answers || Engineering Geology MCQ Questions and Answers || Engineering Geology GK Questions and Answers || GK on Engineering Geology