An instrument has \( 0.1 \) per cent stray light. Its maximum measurable absorbance is about
Answer: D
Even with the sample absorbing everything, the stray light still reaches the detector:
\[ A_{max} = -\log_{10}(0.001) = 3 \]
giving about 3, and readings approaching it are increasingly compressed and non-linear. Reducing stray light by a factor of ten buys one more unit of absorbance, which is why high-absorbance work needs a double monochromator rather than a better detector.
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